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anonymous
 4 years ago
Need help with a related rates calculus problem! I'll type it!
anonymous
 4 years ago
Need help with a related rates calculus problem! I'll type it!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A candy company needs a custom box for their truffles. The box they've chosen is in the shape of a cylinder with a hemisphere of the same radius on top. The total volume of the box is V= 1/2(4r^2pi/3) + r^2pi(yr), where y is the height of the box and r is the radius. Originally the candy box was designed to have a height of 6 inches and a radius of 2, but the shipper suggests that the boxes be made slightly shorter. You now need to adjust the radius so that the height is reduced to 5.75 but the volume remains constant. A. Find the value of dr/dy at the point r =2, r = 6. Help with process

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Just need help getting started.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2mertsj would be surprised if I solved this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why is that? I really don't understand how dy/dr can be taken on that formula. I'll write it out nicer if you like.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1/2(4\pi r^2\div 3)+\pi r^2(yr)=V\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot. Let me know if you need anything else.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Later they ask you to use your dr/dy to change the radius to 5.75.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hero, thank you, but this is free response and I needed help with the process.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can anyone help me with the process?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Maybe. Do you know how to take the derivative of Volume?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes. Typically though, it is d/dt. That is what is tripping me up. This time it is dr/dy. What changes?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2derivative of the radius with respect to y, rather than t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, when you end up taking the derivative of an 'y' values, you get dr/dy? ex. dr/dy(2y^2) = 4y dr/dy?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I suppose my question is this: What happens mathematically when you take the derivative of radius in respect to height?

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Well, it doesn't exactly work like that but you're on the right track. If you have an expression with y and you take the derivative of r with respect to y, you take the derivative normally, then tack on the dr/dy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. That _doesn't_ happen with 'r' terms though.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2You take the derivative with r as normal. The derivative of r with respect to y only applies to the y variable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you! That's what I needed to know.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Tell mertsj that I helped you. When you get the answer, let me know. I probably shouldn't have told you so early.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2You do realize that finding dr/dy is only the first part. The second part is, you have to replace y = 5.75 to find r while keeping the volume constant

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Honestly, I don't know how to tell him if he's not online, but if I see him chatting I will; I'm fairly new here. I will let you know when I get the answer. Thank you, and yes, I figured that part out. It was the implicit stuff that was killing me.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2:D Okay, glad to help you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And thank you for your time :)

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Actually, we can go to a site called vyew

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Then I can watch you do the steps

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Uhh, is that...video chat? Because I think I'll pass for the afternoon, thanks.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm very close to the answer, just give me another minute or two.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2It's not video chat. Why does everyone automatically assume video chat?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Might have to do with the 'watch' part.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2It's just a site with an online whiteboard

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. I've got a tablet. My handwriting should be decent.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Yes, your handwriting was very nice. I figured you must have a tablet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, man. Let me keep working and see if I can figure out what I did wrong. I don't know why my microphone wouldn't work.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Well, I think it would be better if you worked on the mic, but okay

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got 1/5 this time. I'm checking wolframalpha.
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