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anonymous

  • 4 years ago

A school club sold 25 boxes of cookies. Two kinds were sold. The chocalate cookies cost $3.00 a box. The vanilla cookies cost $4.00 per box. The club collected $88.00. How many boxes of each type were sold?

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  1. anonymous
    • 4 years ago
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    sorry i just have to get this done by 4:00 and i dont understand it

  2. anonymous
    • 4 years ago
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    i need how u got it too if thats ok

  3. ash2326
    • 4 years ago
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    Let the no. of chocolate cookies boxes sold be x and no. of vanilla cookies boxes sold be y, we 're given total no. of boxes sold is 25 so we get x+y=25

  4. ash2326
    • 4 years ago
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    The price of chocolate cookie box is $3 and vanilla cookie box cost $4 it's given the club collected $88 so 3x+4y=88 we have two equations x+y=25 and 3x+4y=88

  5. ash2326
    • 4 years ago
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    Can you solve the equations to find x and y?

  6. anonymous
    • 4 years ago
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    Ash 2326 do you mind helping me with my problem once you are done?

  7. ash2326
    • 4 years ago
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    Not at all, I'll help you

  8. anonymous
    • 4 years ago
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    i dont really kno how to solve them

  9. ash2326
    • 4 years ago
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    we have 1st.......x+y=25 2nd......3x+4y=88 Multiply Ist by 3 , we get 3x+3y=75 now subtract this from 2nd we get \[(3x+4y)-(3x+3y)=88-75\] \[4y-3y=13\] we get y=13 nox x+y=25 so x+13=25 x=12 12 chocloate cookie boxes 13 vanilla cookie boxes

  10. anonymous
    • 4 years ago
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    so thats the answer?

  11. ash2326
    • 4 years ago
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    yeah, :)

  12. anonymous
    • 4 years ago
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    thank u so much!!

  13. ash2326
    • 4 years ago
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    welcome :)

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