anonymous
  • anonymous
Did I do this problem right? Warning: It's Very Long!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Step 1: Pick a friend or family member to be the character of your word problem. This friend or family member may do one of the following: • Drive a boat • Drive a jet ski My father, Wayne, will be driving a boat. Step 2: Select a current speed of the water in mph. The current speed will be 7 mph. Step 3: Select the number of hours (be reasonable please) that your friend or family member drove the boat or jets ski against the current speed you chose in step 2. My father had to sail the boat upstream 60 miles in approximately 6 hours Step 4: Select the number of hours that your friend or family member made the same trip with the current (this should be a smaller number, as your friend or family member will be traveling with the current). He will then have to sail the boat downstream for 72 miles in no less than 3 hours. Step 5: Write out the word problem you created and calculate how fast your friend or family member was traveling in still water. Round your answer to the nearest mph. Wayne decided he wanted to take his daughter out for an all-day fishing trip. So, they packed up the truck and readied the fishing boat and high tailed it to the nearest doc. To get to his secret fishing spot, Wayne had to sail the boat upstream 60 miles in no less than 6 hours and then back downstream in no less than 3 hours, that is, if they want to make it home for dinner. Determine the speed Wayne must sail in still waters in order to make it home in time for dinner? 4. Follow the 5 steps below to complete this problem. (4 points) My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(b-c) Downstream: 72 = 3(b+c) There are now two separate equations: 60 = 6b - 6c and 72 = 3b + 3c Solve both equations for b: b = 10 + c b = 24 - c Now make both equations equal each other and solve for c: 10 + c = 24 - c 2c = 14 c = 7 The speed of the current was 7 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 7 b = 17 The speed of the boat in still water must remain a consistent 17 mph or more in order for Wayne and his daughter to make it home in time or dinner.
anonymous
  • anonymous
I know it looks extremely long but it's actually all part of the same question. If someone could just look over and tell me if I did it correctly, I would be truly grateful!!
phi
  • phi
my only quibble is that they want Select the number of hours that your friend or family member made the *same trip* with the current so you should go downstream only 60 miles rather than 72 miles. (Anyway, isn't that where you parked to car?)

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anonymous
  • anonymous
ohh okay, I see now. Thanks, I missed that.. lol :D
phi
  • phi
but otherwise, it looks good.
anonymous
  • anonymous
Cool, thank you so much! :)
phi
  • phi
nearest doc. should be nearest dock.
anonymous
  • anonymous
haha thanks, btw wouldn't I have to change the whole solution if I change the one variable to 60 instead of 72?
phi
  • phi
definitely must change your solution, but it is not too hard (at least for me)...
anonymous
  • anonymous
haha funny... lets see how this works out. Im not very quick with this sort of stuff so It may take me a while. hahaha it took me forever to finish the first one, lol thanks again :)
anonymous
  • anonymous
Okay, here is my new solution: My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(b-c) Downstream: 60 = 3(b+c) There are now two separate equations: 60 = 6b - 6c and 60 = 3b + 3c Solve both equations for b: b = 10 + c b = 10 - c Now make both equations equal each other and solve for c: 10 + c = 10 - c 2c = 0 c = 0 The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 0 b = 10 The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner. Is that better?
phi
  • phi
check this 60 = 3b + 3c
anonymous
  • anonymous
ohh your right! That would end up like this: 60 = 3(10) + 3(0) and that wouldn't work. What do I do?
phi
  • phi
redo 60= 3b+3c (solve for b, only doing it more carefully)
anonymous
  • anonymous
would 20 work?
phi
  • phi
yes. you can divide each term by 3 to get 20= b+c b= 20 - c somehow you got b = 10 - c , which isn't right.
anonymous
  • anonymous
I got confused I guess, haha
phi
  • phi
so pick up with Solve both equations for b: b = 10 + c b = 20 - c
anonymous
  • anonymous
Now make both equations equal each other and solve for c: 10 + c = 20 - c 2c = 10 c = 5 The speed of the current was 5 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 5 b = 15 The speed of the boat in still water must remain a consistent 15 mph or more in order for Wayne and his daughter to make it home in time or dinner. Better?
phi
  • phi
yes, perfect.
anonymous
  • anonymous
Awesome!! Thanks again!!
anonymous
  • anonymous
I have the same question but different numbers. I don't get how you did this could you help. 20 = 4 (b - c) 45 = 2 (b + c)
anonymous
  • anonymous
It is the same question as Renee99 at the top just with different numbers

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