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anonymous

  • 4 years ago

Did I do this problem right? Warning: It's Very Long!!

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  1. anonymous
    • 4 years ago
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    Step 1: Pick a friend or family member to be the character of your word problem. This friend or family member may do one of the following: • Drive a boat • Drive a jet ski My father, Wayne, will be driving a boat. Step 2: Select a current speed of the water in mph. The current speed will be 7 mph. Step 3: Select the number of hours (be reasonable please) that your friend or family member drove the boat or jets ski against the current speed you chose in step 2. My father had to sail the boat upstream 60 miles in approximately 6 hours Step 4: Select the number of hours that your friend or family member made the same trip with the current (this should be a smaller number, as your friend or family member will be traveling with the current). He will then have to sail the boat downstream for 72 miles in no less than 3 hours. Step 5: Write out the word problem you created and calculate how fast your friend or family member was traveling in still water. Round your answer to the nearest mph. Wayne decided he wanted to take his daughter out for an all-day fishing trip. So, they packed up the truck and readied the fishing boat and high tailed it to the nearest doc. To get to his secret fishing spot, Wayne had to sail the boat upstream 60 miles in no less than 6 hours and then back downstream in no less than 3 hours, that is, if they want to make it home for dinner. Determine the speed Wayne must sail in still waters in order to make it home in time for dinner? 4. Follow the 5 steps below to complete this problem. (4 points) My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(b-c) Downstream: 72 = 3(b+c) There are now two separate equations: 60 = 6b - 6c and 72 = 3b + 3c Solve both equations for b: b = 10 + c b = 24 - c Now make both equations equal each other and solve for c: 10 + c = 24 - c 2c = 14 c = 7 The speed of the current was 7 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 7 b = 17 The speed of the boat in still water must remain a consistent 17 mph or more in order for Wayne and his daughter to make it home in time or dinner.

  2. anonymous
    • 4 years ago
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    I know it looks extremely long but it's actually all part of the same question. If someone could just look over and tell me if I did it correctly, I would be truly grateful!!

  3. phi
    • 4 years ago
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    my only quibble is that they want Select the number of hours that your friend or family member made the *same trip* with the current so you should go downstream only 60 miles rather than 72 miles. (Anyway, isn't that where you parked to car?)

  4. anonymous
    • 4 years ago
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    ohh okay, I see now. Thanks, I missed that.. lol :D

  5. phi
    • 4 years ago
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    but otherwise, it looks good.

  6. anonymous
    • 4 years ago
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    Cool, thank you so much! :)

  7. phi
    • 4 years ago
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    nearest doc. should be nearest dock.

  8. anonymous
    • 4 years ago
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    haha thanks, btw wouldn't I have to change the whole solution if I change the one variable to 60 instead of 72?

  9. phi
    • 4 years ago
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    definitely must change your solution, but it is not too hard (at least for me)...

  10. anonymous
    • 4 years ago
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    haha funny... lets see how this works out. Im not very quick with this sort of stuff so It may take me a while. hahaha it took me forever to finish the first one, lol thanks again :)

  11. anonymous
    • 4 years ago
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    Okay, here is my new solution: My Solution: c = current of river b = rate of boat d = s(t) will represent (distance = speed X time) Upstream: 60 = 6(b-c) Downstream: 60 = 3(b+c) There are now two separate equations: 60 = 6b - 6c and 60 = 3b + 3c Solve both equations for b: b = 10 + c b = 10 - c Now make both equations equal each other and solve for c: 10 + c = 10 - c 2c = 0 c = 0 The speed of the current was 0 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 0 b = 10 The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner. Is that better?

  12. phi
    • 4 years ago
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    check this 60 = 3b + 3c

  13. anonymous
    • 4 years ago
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    ohh your right! That would end up like this: 60 = 3(10) + 3(0) and that wouldn't work. What do I do?

  14. phi
    • 4 years ago
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    redo 60= 3b+3c (solve for b, only doing it more carefully)

  15. anonymous
    • 4 years ago
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    would 20 work?

  16. phi
    • 4 years ago
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    yes. you can divide each term by 3 to get 20= b+c b= 20 - c somehow you got b = 10 - c , which isn't right.

  17. anonymous
    • 4 years ago
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    I got confused I guess, haha

  18. phi
    • 4 years ago
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    so pick up with Solve both equations for b: b = 10 + c b = 20 - c

  19. anonymous
    • 4 years ago
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    Now make both equations equal each other and solve for c: 10 + c = 20 - c 2c = 10 c = 5 The speed of the current was 5 mph Now, plug the numbers into one of either the original equations to find the speed of the boat in still water. I chose the first equation: b = 10 + c or b = 10 + 5 b = 15 The speed of the boat in still water must remain a consistent 15 mph or more in order for Wayne and his daughter to make it home in time or dinner. Better?

  20. phi
    • 4 years ago
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    yes, perfect.

  21. anonymous
    • 4 years ago
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    Awesome!! Thanks again!!

  22. anonymous
    • 3 years ago
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    I have the same question but different numbers. I don't get how you did this could you help. 20 = 4 (b - c) 45 = 2 (b + c)

  23. anonymous
    • 3 years ago
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    It is the same question as Renee99 at the top just with different numbers

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