Did I do this problem right? Warning: It's Very Long!!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

Did I do this problem right? Warning: It's Very Long!!

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Step 1:
Pick a friend or family member to be the character of your word problem. This friend or family member may do one of the following:
• Drive a boat
• Drive a jet ski
My father, Wayne, will be driving a boat.
Step 2:
Select a current speed of the water in mph.
The current speed will be 7 mph.
Step 3:
Select the number of hours (be reasonable please) that your friend or family member drove the boat or jets ski against the current speed you chose in step 2.
My father had to sail the boat upstream 60 miles in approximately 6 hours
Step 4:
Select the number of hours that your friend or family member made the same trip with the current (this should be a smaller number, as your friend or family member will be traveling with the current).
He will then have to sail the boat downstream for 72 miles in no less than 3 hours.
Step 5:
Write out the word problem you created and calculate how fast your friend or family member was traveling in still water. Round your answer to the nearest mph.
Wayne decided he wanted to take his daughter out for an all-day fishing trip. So, they packed up the truck and readied the fishing boat and high tailed it to the nearest doc. To get to his secret fishing spot, Wayne had to sail the boat upstream 60 miles in no less than 6 hours and then back downstream in no less than 3 hours, that is, if they want to make it home for dinner. Determine the speed Wayne must sail in still waters in order to make it home in time for dinner?
4. Follow the 5 steps below to complete this problem. (4 points)
My Solution:
c = current of river
b = rate of boat
d = s(t) will represent (distance = speed X time)
Upstream: 60 = 6(b-c)
Downstream: 72 = 3(b+c)
There are now two separate equations:
60 = 6b - 6c
and
72 = 3b + 3c
Solve both equations for b:
b = 10 + c
b = 24 - c
Now make both equations equal each other and solve for c:
10 + c = 24 - c
2c = 14
c = 7
The speed of the current was 7 mph
Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation:
b = 10 + c
or
b = 10 + 7
b = 17
The speed of the boat in still water must remain a consistent 17 mph or more in order for Wayne and his daughter to make it home in time or dinner.

- anonymous

I know it looks extremely long but it's actually all part of the same question. If someone could just look over and tell me if I did it correctly, I would be truly grateful!!

- phi

my only quibble is that they want
Select the number of hours that your friend or family member made the *same trip* with the current
so you should go downstream only 60 miles rather than 72 miles. (Anyway, isn't that where you parked to car?)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

ohh okay, I see now. Thanks, I missed that.. lol :D

- phi

but otherwise, it looks good.

- anonymous

Cool, thank you so much! :)

- phi

nearest doc. should be nearest dock.

- anonymous

haha thanks, btw wouldn't I have to change the whole solution if I change the one variable to 60 instead of 72?

- phi

definitely must change your solution, but it is not too hard (at least for me)...

- anonymous

haha funny... lets see how this works out. Im not very quick with this sort of stuff so It may take me a while. hahaha it took me forever to finish the first one, lol thanks again :)

- anonymous

Okay, here is my new solution:
My Solution:
c = current of river
b = rate of boat
d = s(t) will represent (distance = speed X time)
Upstream: 60 = 6(b-c)
Downstream: 60 = 3(b+c)
There are now two separate equations:
60 = 6b - 6c
and
60 = 3b + 3c
Solve both equations for b:
b = 10 + c
b = 10 - c
Now make both equations equal each other and solve for c:
10 + c = 10 - c
2c = 0
c = 0
The speed of the current was 0 mph
Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation:
b = 10 + c
or
b = 10 + 0
b = 10
The speed of the boat in still water must remain a consistent 10 mph or more in order for Wayne and his daughter to make it home in time or dinner.
Is that better?

- phi

check this
60 = 3b + 3c

- anonymous

ohh your right! That would end up like this: 60 = 3(10) + 3(0) and that wouldn't work. What do I do?

- phi

redo 60= 3b+3c (solve for b, only doing it more carefully)

- anonymous

would 20 work?

- phi

yes. you can divide each term by 3 to get
20= b+c
b= 20 - c
somehow you got b = 10 - c , which isn't right.

- anonymous

I got confused I guess, haha

- phi

so pick up with
Solve both equations for b:
b = 10 + c
b = 20 - c

- anonymous

Now make both equations equal each other and solve for c:
10 + c = 20 - c
2c = 10
c = 5
The speed of the current was 5 mph
Now, plug the numbers into one of either the original equations to find the speed of the boat in still water.
I chose the first equation:
b = 10 + c
or
b = 10 + 5
b = 15
The speed of the boat in still water must remain a consistent 15 mph or more in order for Wayne and his daughter to make it home in time or dinner.
Better?

- phi

yes, perfect.

- anonymous

Awesome!! Thanks again!!

- anonymous

I have the same question but different numbers. I don't get how you did this could you help.
20 = 4 (b - c)
45 = 2 (b + c)

- anonymous

It is the same question as Renee99 at the top just with different numbers

Looking for something else?

Not the answer you are looking for? Search for more explanations.