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\[2\sin x(\cos x-1)\neq0\]try it on your calculator

the 2 makes no difference so the assertion is that\[\sin x(\cos x-1)=0\]which is just wrong

...as an identity I mean

but that's just going on that part of the formula

ok I see your problem...

sorry I forgot to mention that the domain is restricted to [0,2pi]

no big deal with the domain, makes it simpler

oh ok I see :) thanks ugh

welcome!