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anonymous

  • 4 years ago

systems of equations : y=x-3 4x+y=32 how do you solve this?

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  1. anonymous
    • 4 years ago
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    You know that y=x-3. You can use this in y our second equation to solve for x 4x+(x-3)=32 5x-3=32 5x=35 x=7 Now you know x, so you can substitute 7 for x in y=x-3. y=7-3=4 You can check if it's correct by plugging both values back into the other equation: 4(7)+4=32=28+4=32. The expression is true, so those are the solutions.

  2. anonymous
    • 4 years ago
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    wait is y already solved?

  3. anonymous
    • 4 years ago
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    No, y is not already solved. I had to solve it after I found x here. We substituted x-3 for y in the other equation so we could solve for x.

  4. anonymous
    • 4 years ago
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    \[4x+y=4x+(x-3)=32\]

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