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anonymous
 4 years ago
systems of equations : y=x3
4x+y=32
how do you solve this?
anonymous
 4 years ago
systems of equations : y=x3 4x+y=32 how do you solve this?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You know that y=x3. You can use this in y our second equation to solve for x 4x+(x3)=32 5x3=32 5x=35 x=7 Now you know x, so you can substitute 7 for x in y=x3. y=73=4 You can check if it's correct by plugging both values back into the other equation: 4(7)+4=32=28+4=32. The expression is true, so those are the solutions.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wait is y already solved?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, y is not already solved. I had to solve it after I found x here. We substituted x3 for y in the other equation so we could solve for x.
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