anonymous
  • anonymous
systems of equations : y=x-3 4x+y=32 how do you solve this?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
You know that y=x-3. You can use this in y our second equation to solve for x 4x+(x-3)=32 5x-3=32 5x=35 x=7 Now you know x, so you can substitute 7 for x in y=x-3. y=7-3=4 You can check if it's correct by plugging both values back into the other equation: 4(7)+4=32=28+4=32. The expression is true, so those are the solutions.
anonymous
  • anonymous
wait is y already solved?
anonymous
  • anonymous
No, y is not already solved. I had to solve it after I found x here. We substituted x-3 for y in the other equation so we could solve for x.

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anonymous
  • anonymous
\[4x+y=4x+(x-3)=32\]

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