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anonymous
 4 years ago
IF X=18 (+ or ) 0.5 and Y= 9.0 (+ or ) 0.4, find appropriate values, including errors, for:
X+Y
XY
X+2Y
2X3Y
X * Y
X / Y
sqr(XY
XY^3
anonymous
 4 years ago
IF X=18 (+ or ) 0.5 and Y= 9.0 (+ or ) 0.4, find appropriate values, including errors, for: X+Y XY X+2Y 2X3Y X * Y X / Y sqr(XY XY^3

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If we wanted to include the endpoints we would write [2,4]. If we wanted to ...... \frac{1}{xy^5}. 35. \sqrt{x^2y^4}. xy2. 36. \bigg(\frac{8x^6}{y^4}\. \frac{2x^2}{y^{4/3}}

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02.5 Mean Square Approximation and Parseval's Identity 16 .... ((x + 3)( U−3 − U−2) + (2x + 5)( U−2 − U−1) + (x + 4)( U−1 − U0) ... 18 x cos 3x + ∑. 6 n=1, n=3 sin nx n(9−n2) . # 49: yp = ... ↔ yp = x(.... # 67: y = − .... Same reasoning as in the previous exercise, we find the solution ...... So u(xy) = T if and only if 2xy = T if and only

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this doesnt make any sense, are you sure your doing it the right way

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here let me put it another way

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all we have to do is add X +Y for the first one 18 + 9.0 = 27 then do you just add the uncertainties? .5+.4= .9 27 + or  .9 ???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If we wanted to include the endpoints we would write [2,4]. 2.5 Mean Square Approximation and Parseval's Identity 16 .... ((x + 3)( U−3 − U−2) + (2x + 5)( U−2 − U−1) + (x + 4)( U−1 − U0) ... 18 x cos 3x + ∑. 6 n=1, n=3 sin nx n(9−n2) .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Same reasoning as in the previous exercise, we find the solution ...... So u(xy) = T if and only if 2xy = T if and only

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No this is none of that, this is physics lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is my answer correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Of course. yes yes yes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so you add the uncertainties?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x+2Y = 36 + or  0.9??
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