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anonymous
 4 years ago
What is the concentration in M of KCl in a solution made by mixing 25.0ml of 0.175M KCl with 50.0ml of 0.175M KCl
anonymous
 4 years ago
What is the concentration in M of KCl in a solution made by mixing 25.0ml of 0.175M KCl with 50.0ml of 0.175M KCl

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you think this one is solved?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would thing 25 times .175 divided by 50

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thats what i would think also

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesnt work though

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0try putting in 0.175 M KCl

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you mix two solutions with the same concentration, I'd think that the concentration would stay the same. There's no reason it wouldn't. If you separated a 1L sample of .175 M KCl into two 500mL samples, they both will be the same concentration. Put them back together, and they are still .175M. To do it more analytically, try this: Find how many moles of KCl are in each of the two solutions. This is how many moles will be present in the final, mixed solution. Then using the molar concentration equation...\[c_i=\frac{mols\ KCl}{V_{sol'n}}\]And obviously, if you mix a 50mL sample with a 25mL sample, you will get 75mL, assuming the volumes are additive. You'll find that the concentration is indeed the 0.175M.
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