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anonymous
 4 years ago
Can I integrate the function like this?
anonymous
 4 years ago
Can I integrate the function like this?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328569318716:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328569348044:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i integrate it like this?

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.3use 2x+1=t and you can solve it relatively easy :D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya i will use subsitution. it is the easiest for me

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0fraction simplifying would have been correct if the equation was\[\int\limits_{}^{}(2x+1)/X^2\]

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0int by parts is what I would try ...

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0because x^2 goes down and (2x+1)^1 goes up ... im just sayingid try it :)

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.3there are thousands of ways...:D

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0I think nenad's is simplest

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 +(2x+1) 1/3 x^3 x 1/12 x^4 +1 1/60 x^5 0 .......... something like that maybe :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0umm what is that suppossed to be?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0its spose to be correct, but I forgot how to derive 2x ....

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0its integration by parts with a table for ease of sorting information

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhh i seee lol ok Thanks

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0x^2 +(2x+1) 1/3 x^3 2 1/12 x^4 0 .......... \[\frac{1}{3}x^3(2x+1)\frac{2}{12}x^4\] with any luck ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0when i used sub i got a totally diff answer but that is ok?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0that becasue I forget that 2x+1 is a denom and shoulda 1 ed it

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0but, if you ever have\[\int (2x+1)x^2dx\]its good lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0lol i will keep that in mind

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0since hte bottom is a degree 1 and the top a degree 2 youd prolly wanna go ahead and simplify with the divide

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1328570160380:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.01/2 x 1/4  2x+1 ) x^2 (x^2 + 1/2x)  1/2 x (1/2 x  1/4)  +1/4 \[\frac{1}{2}x\frac{1}{4}+\frac{1}{4(2x+1)}\]
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