anonymous
  • anonymous
Can I integrate the function like this?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1328569318716:dw|
anonymous
  • anonymous
|dw:1328569348044:dw|
anonymous
  • anonymous
can i integrate it like this?

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More answers

nenadmatematika
  • nenadmatematika
no you can't
anonymous
  • anonymous
oh ok just wondering
nenadmatematika
  • nenadmatematika
use 2x+1=t and you can solve it relatively easy :D
anonymous
  • anonymous
ya i will use subsitution. it is the easiest for me
anonymous
  • anonymous
fraction simplifying would have been correct if the equation was\[\int\limits_{}^{}(2x+1)/X^2\]
anonymous
  • anonymous
oh ok. Thanks :DD
amistre64
  • amistre64
int by parts is what I would try ...
anonymous
  • anonymous
y?
amistre64
  • amistre64
because x^2 goes down and (2x+1)^-1 goes up ... im just sayingid try it :)
amistre64
  • amistre64
or the other way lol
nenadmatematika
  • nenadmatematika
there are thousands of ways...:D
TuringTest
  • TuringTest
I think nenad's is simplest
amistre64
  • amistre64
x^2 +(2x+1) 1/3 x^3 -x 1/12 x^4 +1 1/60 x^5 0 .......... something like that maybe :)
anonymous
  • anonymous
umm what is that suppossed to be?
amistre64
  • amistre64
its spose to be correct, but I forgot how to derive 2x ....
amistre64
  • amistre64
its integration by parts with a table for ease of sorting information
anonymous
  • anonymous
ohhh i seee lol ok Thanks
amistre64
  • amistre64
x^2 +(2x+1) 1/3 x^3 -2 1/12 x^4 0 .......... \[\frac{1}{3}x^3(2x+1)-\frac{2}{12}x^4\] with any luck ;)
anonymous
  • anonymous
when i used sub i got a totally diff answer but that is ok?
amistre64
  • amistre64
that becasue I forget that 2x+1 is a denom and shoulda -1 ed it
amistre64
  • amistre64
but, if you ever have\[\int (2x+1)x^2dx\]its good lol
anonymous
  • anonymous
lol i will keep that in mind
amistre64
  • amistre64
since hte bottom is a degree 1 and the top a degree 2 youd prolly wanna go ahead and simplify with the divide
nenadmatematika
  • nenadmatematika
|dw:1328570160380:dw|
amistre64
  • amistre64
1/2 x -1/4 ----------- 2x+1 ) x^2 (x^2 + 1/2x) ------------- -1/2 x (-1/2 x - 1/4) ------------- +1/4 \[\frac{1}{2}x-\frac{1}{4}+\frac{1}{4(2x+1)}\]
anonymous
  • anonymous
Thanks :D

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