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anonymous

  • 4 years ago

Can I integrate the function like this?

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  1. anonymous
    • 4 years ago
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    |dw:1328569318716:dw|

  2. anonymous
    • 4 years ago
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    |dw:1328569348044:dw|

  3. anonymous
    • 4 years ago
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    can i integrate it like this?

  4. nenadmatematika
    • 4 years ago
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    no you can't

  5. anonymous
    • 4 years ago
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    oh ok just wondering

  6. nenadmatematika
    • 4 years ago
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    use 2x+1=t and you can solve it relatively easy :D

  7. anonymous
    • 4 years ago
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    ya i will use subsitution. it is the easiest for me

  8. anonymous
    • 4 years ago
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    fraction simplifying would have been correct if the equation was\[\int\limits_{}^{}(2x+1)/X^2\]

  9. anonymous
    • 4 years ago
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    oh ok. Thanks :DD

  10. amistre64
    • 4 years ago
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    int by parts is what I would try ...

  11. anonymous
    • 4 years ago
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    y?

  12. amistre64
    • 4 years ago
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    because x^2 goes down and (2x+1)^-1 goes up ... im just sayingid try it :)

  13. amistre64
    • 4 years ago
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    or the other way lol

  14. nenadmatematika
    • 4 years ago
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    there are thousands of ways...:D

  15. TuringTest
    • 4 years ago
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    I think nenad's is simplest

  16. amistre64
    • 4 years ago
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    x^2 +(2x+1) 1/3 x^3 -x 1/12 x^4 +1 1/60 x^5 0 .......... something like that maybe :)

  17. anonymous
    • 4 years ago
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    umm what is that suppossed to be?

  18. amistre64
    • 4 years ago
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    its spose to be correct, but I forgot how to derive 2x ....

  19. amistre64
    • 4 years ago
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    its integration by parts with a table for ease of sorting information

  20. anonymous
    • 4 years ago
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    ohhh i seee lol ok Thanks

  21. amistre64
    • 4 years ago
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    x^2 +(2x+1) 1/3 x^3 -2 1/12 x^4 0 .......... \[\frac{1}{3}x^3(2x+1)-\frac{2}{12}x^4\] with any luck ;)

  22. anonymous
    • 4 years ago
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    when i used sub i got a totally diff answer but that is ok?

  23. amistre64
    • 4 years ago
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    that becasue I forget that 2x+1 is a denom and shoulda -1 ed it

  24. amistre64
    • 4 years ago
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    but, if you ever have\[\int (2x+1)x^2dx\]its good lol

  25. anonymous
    • 4 years ago
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    lol i will keep that in mind

  26. amistre64
    • 4 years ago
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    since hte bottom is a degree 1 and the top a degree 2 youd prolly wanna go ahead and simplify with the divide

  27. nenadmatematika
    • 4 years ago
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    |dw:1328570160380:dw|

  28. amistre64
    • 4 years ago
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    1/2 x -1/4 ----------- 2x+1 ) x^2 (x^2 + 1/2x) ------------- -1/2 x (-1/2 x - 1/4) ------------- +1/4 \[\frac{1}{2}x-\frac{1}{4}+\frac{1}{4(2x+1)}\]

  29. anonymous
    • 4 years ago
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    Thanks :D

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