anonymous
  • anonymous
Ok can anyone please help me understand the pythagorean theorom please ?
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
In a right triangle, the square of the hypotenuse equals the sum of the squares of the other two legs.
pokemon23
  • pokemon23
|dw:1328570206293:dw|
anonymous
  • anonymous
|dw:1328570208471:dw| \[h=\sqrt{a^2+b^2}\] \[a=\sqrt{h^2-b^2}\] \[b=\sqrt{h^2-a^2}\]

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anonymous
  • anonymous
\[h^2=a^2+b^2\]
TuringTest
  • TuringTest
here is a nice visual proof http://www.google.com/imgres?q=pythagorean+theorem&hl=en&sa=X&biw=1024&bih=655&tbm=isch&prmd=imvns&tbnid=0a8M5qnfEI1lGM:&imgrefurl=http://www.math-aids.com/Pythagorean_Theorem/&docid=mrZX0eSmrJiEWM&imgurl=http://www.math-aids.com/images/pythagorean-definition-04.png&w=612&h=792&ei=GGAwT4XWHqLb0QGnhLHUCg&zoom=1&iact=hc&vpx=560&vpy=273&dur=0&hovh=255&hovw=197&tx=110&ty=274&sig=107113811444028023167&page=1&tbnh=130&tbnw=88&start=0&ndsp=16&ved=1t:429,r:13,s:0
anonymous
  • anonymous
All right i understand all that but where do the square roots come in like if i give you a problem would you be able to help ?
pokemon23
  • pokemon23
where c represents the length of the hypotenuse, and a and b represent the lengths of the other two sides.
pokemon23
  • pokemon23
In any right triangle, the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares whose sides are the two legs (the two sides that meet at a right angle).
anonymous
  • anonymous
The square roots come in because the pythagorean theorem tells you the sum of the squares of the legs equal the square of the hypotenuse. You have to use the square root to find the number. \[(\sqrt{a^2})=a\]
pokemon23
  • pokemon23
|dw:1328570575319:dw|
anonymous
  • anonymous
|dw:1328570529625:dw| how would i find the answers to that ?
anonymous
  • anonymous
Here, you wouldn't use the pythagorean theorem until you use some trig to find one side.
pokemon23
  • pokemon23
for example in this question we need to find c^2 by finding c^2 we plug in the formula a^2+b^2=c^2 6^2+7^2=c^2 36+48=c^2 \[\sqrt{36}\]+\[\sqrt{48}\]
pokemon23
  • pokemon23
I mean 49*
anonymous
  • anonymous
\[\tan(60º)=\frac{9\sqrt{3}}{x}\] \[x=\frac{9\sqrt{3}}{\tan(60º)}\]
anonymous
  • anonymous
When you find x, now you can use the pythagorean theorem. \[y=\sqrt{x^2+(9\sqrt{3})^2}\]
anonymous
  • anonymous
oh man my teacher never told me we had to use tan to solve this answer
anonymous
  • anonymous
Well, this is a special right triangle, so I suppose you don't have to use trig. It is a 30-60-90 triangle, did your teacher tell you how to solve these?
anonymous
  • anonymous
http://www.cliffsnotes.com/study_guide/Special-Right-Triangles.topicArticleId-18851,articleId-18821.html Look at this link, it tells you the relationship between sides in special right triangles so you don't have to use trig.
anonymous
  • anonymous
ok i understand that now do you think you could give me a problem so i could try to answer it
anonymous
  • anonymous
|dw:1328571722764:dw|
anonymous
  • anonymous
Can you do that one?
anonymous
  • anonymous
for this one what do i have to find ?
anonymous
  • anonymous
so the short leg would be 5 and the hyp would 25 ?

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