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anonymous
 4 years ago
how do i simplify nested roots and powers of a single positive variable?
anonymous
 4 years ago
how do i simplify nested roots and powers of a single positive variable?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\large (x^a)^b=x^{ab}\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[b]{x^a}=x^{a/b}\]so those can be used together

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how would i solve this type of problem then?dw:1328571176207:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0raise the equation to the power if 6 then simplify, then take it to the 1/6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how'd u get that... if you don't mind.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0got rid of the radicals, using the power rules. easily all you have to do is take the product of each of the nested radicals. make sure you dont forget to apply the power non nested equation. this was simple equation when you get (x +2 + (x)^1/2))^1/2 it becomes very difficult

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328571786972:dw lol. is this what you do though? I know i got a different answer...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1I can't see the whole problem, is it an equation or simplification?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x\sqrt[3]{x^2}}\]is all I can see, is there more?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use the first power rule given by turing test

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont understand why i would use the first one and not the second

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\large\sqrt{x\sqrt[3]{x^2}}=(x\cdot x^{3/2})^{1/2}=x^{1/2}\cdot x^{(3/2)\cdot(1/2)}\]simplify the fractions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0same principal different ways of represent the function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328572233670:dw

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1we use four rules here really:\[\sqrt[b]{x^a}=x^{a/b}\]\[(xy)^a=x^ay^a\]\[(x^a)^b=x^{ab}\]\[x^ax^b=x^{a+b}\]\[\large\sqrt{x\sqrt[3]{x^2}}=(x\cdot x^{3/2})^{1/2}=x^{1/2}\cdot x^{(3/2)\cdot(1/2)}\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1or if you prefer\[\large\sqrt{x\sqrt[3]{x^2}}=(x\cdot x^{\frac32})^{\frac12}=(x^{1+\frac32})^{\frac12}=x^{(\frac52\cdot\frac12)}=x^{\frac54}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0gotttttttt it. ty test
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