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anonymous
 4 years ago
A wooden plank is inclined at and angle of 23 degrees above the horizontal. A 2.0 kg box attached to a rope is is pulled up the incline. The coefficient of kinetic friction between the box and the wooden plank is 0.15.
What does the tension in the rope is the box moves up the incline at a constant velocity?
anonymous
 4 years ago
A wooden plank is inclined at and angle of 23 degrees above the horizontal. A 2.0 kg box attached to a rope is is pulled up the incline. The coefficient of kinetic friction between the box and the wooden plank is 0.15. What does the tension in the rope is the box moves up the incline at a constant velocity?

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TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1here's a basic diagramdw:1329436877812:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Got it............. Im having problems knowing what the tension it is referring to actually is...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1...now let's do a little trigdw:1329436980919:dwwe can use the force of gravity into the surface to find N, which we can use to find friction. we then have\[TfF_g\sin\theta=0\]along the direction of the incline, which we can use to find T. got it from here?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What equation is TfFgsin\[TfFgsin \theta=0?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Would T be the applied force?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1yes, T is the applied force (tension) I got that equation by just summing all the forces along the direction of the ramp, which we know sum to 0 because the object is moving at a constant velocity.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got the X component to be 7.8 and The normal force to be 18.4. Now, Im not sure what to do because the applied force would be 7.8 and it is not the right answer.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sum F=TF_g\sin\thetaf=0\]\[T=F_g\sin\theta+f=mg\sin\theta+\mu N=mg(\sin\theta+\mu \cos\theta)\]\[=2(9.8)[\sin(23^{\circ})+0.15\cos(23^{\circ})]\approx10.36\text{N}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh! Thanks so much!!! I didnt learn that equation yet in school so I was very confused... But I will ask my teacher tomorrow!
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