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anonymous

  • 4 years ago

so i need to solve this equation by useing the square root property 4x^2-28x+49=5

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  1. asnaseer
    • 4 years ago
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    you should be able to factorise the left hand side of this equation

  2. anonymous
    • 4 years ago
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    yes but the factors have to add to = 28

  3. asnaseer
    • 4 years ago
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    correct

  4. asnaseer
    • 4 years ago
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    are you stuck in the factorisation process?

  5. asnaseer
    • 4 years ago
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    you need to end up with something like:\[(...)^2=5\]so see if you can factorise the left hand side such that it becomes something squared, i.e.:\[4x^2-28x+49=(...)^2\]

  6. asnaseer
    • 4 years ago
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    the first term is \(4x^2\) and the term involving x is negative, so we know it must be of the form:\[(2x-???)^2\]

  7. asnaseer
    • 4 years ago
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    does any of this make sense?

  8. anonymous
    • 4 years ago
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    yes thank you

  9. asnaseer
    • 4 years ago
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    ok - so can you see how to factorise the left hand side now?

  10. anonymous
    • 4 years ago
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    yes

  11. asnaseer
    • 4 years ago
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    good - so you know how to solve this equation now?

  12. anonymous
    • 4 years ago
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    yes

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