anonymous
  • anonymous
https://docs.google.com/viewer?a=v&q=cache:oYt47ka7l70J:www.cpo.com/ipcres/pdfs/unit2/Ch4RevQues.pdf+&hl=en&gl=us&pid=bl&srcid=ADGEESj1HjO67kwrGzPsa5R-7C2Hek9yvJv43kvFbNUxKKokbO7Ezx9EryxmavnTz1-4HE4cd-uku0Xeo1vlupXfMmV_QnMX7qa6WfQ3RtchP_GdpiCiZeTytwmyljDEDgLO9owWRzn7&sig=AHIEtbT-lhIJEy39FntuTTp0qi53RVVYIQ last page, #6 ? #help
Physics
schrodinger
  • schrodinger
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anonymous
  • anonymous
arg try to do by your self, I think you can do it ! Just fix the variable F out And use the formula T ( torque ) = F * d.
anonymous
  • anonymous
500 x 5
anonymous
  • anonymous
divided by 35?

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anonymous
  • anonymous
I don't know, i will try to do here
anonymous
  • anonymous
jaw T10= 500N * 10cm = 5000cmN T10=T7= 5000cmN = F * 7cm F = 714N arm T35= 500N * 35cm = 17500cmN T5 = T35 = 17500cmN = F * 5cm F = 3500N o,0 Take your own conclusions :P
anonymous
  • anonymous
this is what i did; 500 x 5 = 2,500 / 35
anonymous
  • anonymous
yep =) sorry, i just want keep this in history, in case of some one else have some problem like that

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