• anonymous
Calculus II - Trig Integration Hey all, just wanted to confirm one answer and likely ask another question in a different thread; $\int\limits_{}^{} 1/(x^2+6x+12) dx$ $(x^2+6x+9) = (x+3)^2 + 3$ $\int\limits_{}^{}1/a^2 + u^2 = (1/a)*\tan^-1(u/a) + C$ $1/\sqrt(3) * \tan^-1 ((x+3)/\sqrt(3)) + C$ Can anyone confirm that answer?
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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