At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

f(t)'=8t -(8)/t^3 for t=-3
-24-8/27
-640/27=-20

Ooop it is not -20 -640/27=-23.7037

yeah I got df/dt=8t-2/t^2 so t=-3 => 8*(-3)-2/(-3)^2 -24-2/9 ! but i dont trust my work

the second term when you differentiated;\[4 \over t ^{2}\]is\[4 t ^{-2}\]becomes \[-8 t ^{-3}\]

or\[-8\over t ^{3}\]

but I would still have to plug in -3 for t

Yes indeed.

wait was I on the right track to getting the answer?

but -640/27=-23.7037 is the answer

right?

Looking at your next to last post. How did you get -640/27? Wouldn't -24 X 27 =-648 ??

It would appear so, if I have kept track of the signs.

But maybe I messed up let me think about this?

lol take your time

ok so the final anwser is -640/27 right? (ill compute it later)

-3 X -3 X -3 = -27 lol

Yes.

Good luck with your studies,and don't err with signs lol

ok thank you very much for the help

ur welcome.