A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Please help... so confused
HOLD ON! im going to draw a picture!
anonymous
 4 years ago
Please help... so confused HOLD ON! im going to draw a picture!

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328575316576:dw solve for x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well i think that would work but we're supposed to make it a proportion

precal
 4 years ago
Best ResponseYou've already chosen the best response.1usually it involves the small triangle vs the large triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ya but i cant do that... at least i dont think i can

precal
 4 years ago
Best ResponseYou've already chosen the best response.1do you know about the angle on top? Is is split in the middle? Is it 45 degrees since the larger part is 90 degrees? I can't tell by your drawing. I know it is hard to draw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well the whole triangle is 90 degrees but it doesnt tell you if its split through the middle

precal
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328575806467:dw if so we can assume the side that is in between them is x...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how can you do that since x is the length of the side on the bottom?

precal
 4 years ago
Best ResponseYou've already chosen the best response.1Is the drawing from a book or a worksheet? the problem with geometry is that you can not assume anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its in the book and ya thats why i dont like it!

precal
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1328575902416:dw We can assume that 90 degrees, the other one we can assume is the 45 degrees because that line that splits the triangle has a special name but I can't recall it at the moment.

precal
 4 years ago
Best ResponseYou've already chosen the best response.1You can scan the picture and attach the file. but I think I might have it figured out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well its online so give me a sec

precal
 4 years ago
Best ResponseYou've already chosen the best response.1\[x^2+x^2=(x+3)^2\] \[2x^2=x^2+6x+9\] \[x^26x9=0\] not that does not work !!!!!

precal
 4 years ago
Best ResponseYou've already chosen the best response.1I meant that does not work!!! Sorry can't seem to type as well

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there is a picture of the problem!

precal
 4 years ago
Best ResponseYou've already chosen the best response.1ok upload it, I will be back in about 5 mins

precal
 4 years ago
Best ResponseYou've already chosen the best response.1ok you got my attention.

precal
 4 years ago
Best ResponseYou've already chosen the best response.1ok x+3 is the leg of the big triangle the hypotenuse is 12x for the big triangle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well the problem never tells you anything about the angles or anything and as you can tell the line doesnt go right through the right angle symbol

precal
 4 years ago
Best ResponseYou've already chosen the best response.1ok x is the leg of the small triangle and x+3 is the hypotenuse of the small triangle there is our proportion

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how did you get 12x since 12 is the whole LARGE triangle's hypotenuse?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im sorry im just super confused!

precal
 4 years ago
Best ResponseYou've already chosen the best response.1No, I think we are ok cross multiply \[12x=(x+3)^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x^2+3x+3x+9=12x x^2+6x+9=12x x^2+9=6x right? but i dont know what do to next because we havent done anything like this in a while!

precal
 4 years ago
Best ResponseYou've already chosen the best response.1x=3 I used the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but how did you get x=3?

precal
 4 years ago
Best ResponseYou've already chosen the best response.1use the quadratic formula

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0see all of that confuses me and i dont think we've done that yet!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well thanks for your help but i dont think im going to get it.... but thank you for your trying... :)

precal
 4 years ago
Best ResponseYou've already chosen the best response.1Is this a challenge question?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont think so.... but online they sometimes leave off something like a picture or a number so that might be what happened... thanks for you patients.

precal
 4 years ago
Best ResponseYou've already chosen the best response.1You will understand this eventually, your teacher has to teach quadratics. One day it will make sense.

precal
 4 years ago
Best ResponseYou've already chosen the best response.1Oh well another reason why computers will not replace teachers. I am sure that it is an oversight of the program. Hang in there :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you and again thanks for your help1
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.