## anonymous 4 years ago a 5kg block is pushed along a level surface by a 40N force at an angle of 30 degrees below the surface. The force of friction action on the block is 10N. What is the acceleration of the block? Normal Force? and Coefficient of kinetic friction.

1. NotTim

As always, I suggest drawing out a diagram, and then creating a variable list.

2. anonymous

well the triangle should be on the other side...hol d on

3. anonymous

|dw:1328577203656:dw|

4. NotTim

Acceleration- F=ma (Rearrange the formula; F uses an angle, and also has a "resistant" frictional force, so remember SOHCAHTOA)

5. NotTim

I think. Don't take my word for it.

6. anonymous

n=mg-Fsintheta

7. NotTim

Whoops. Gotta go...Maybe someone else may help. There's 2 other people here.

8. NotTim

That looks right, but what's n?

9. NotTim

I'll be back in 30min.

10. anonymous

normal force. i think you have to calculate normal fornce to find acceleration

11. anonymous

ok ill still be here. :/

12. anonymous

$(F)\cos(30)= Fx$ $f=\mu F _{N}$ |dw:1328578095405:dw|

13. anonymous

so what is -f in this drawing....

14. anonymous

is it all the forces combined? kinetic friction?

15. anonymous

-f is force of friction that is being Fx is component of the force applied by you so net force in horizontal direction would be |dw:1328602865107:dw| solve for than a gives accel;eration