anonymous
  • anonymous
a 5kg block is pushed along a level surface by a 40N force at an angle of 30 degrees below the surface. The force of friction action on the block is 10N. What is the acceleration of the block? Normal Force? and Coefficient of kinetic friction.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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NotTim
  • NotTim
As always, I suggest drawing out a diagram, and then creating a variable list.
anonymous
  • anonymous
well the triangle should be on the other side...hol d on
anonymous
  • anonymous
|dw:1328577203656:dw|

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More answers

NotTim
  • NotTim
Acceleration- F=ma (Rearrange the formula; F uses an angle, and also has a "resistant" frictional force, so remember SOHCAHTOA)
NotTim
  • NotTim
I think. Don't take my word for it.
anonymous
  • anonymous
n=mg-Fsintheta
NotTim
  • NotTim
Whoops. Gotta go...Maybe someone else may help. There's 2 other people here.
NotTim
  • NotTim
That looks right, but what's n?
NotTim
  • NotTim
I'll be back in 30min.
anonymous
  • anonymous
normal force. i think you have to calculate normal fornce to find acceleration
anonymous
  • anonymous
ok ill still be here. :/
anonymous
  • anonymous
\[(F)\cos(30)= Fx\] \[f=\mu F _{N}\] |dw:1328578095405:dw|
anonymous
  • anonymous
so what is -f in this drawing....
anonymous
  • anonymous
is it all the forces combined? kinetic friction?
anonymous
  • anonymous
-f is force of friction that is being Fx is component of the force applied by you so net force in horizontal direction would be |dw:1328602865107:dw| solve for than a gives accel;eration

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