bimbim2697
  • bimbim2697
Help please graph each linear inequality y>3x-4 x+y<-3 x-2y>-1 x =>-4 y<2 y
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
First graph each as "equality". Depending on the inequality, all points above or below that line will satisfy the inequality.
anonymous
  • anonymous
For example, take y<2. Graph the equality y=2. That will be a horizontal line at y=2. All points below that line will satisfy y<2.
bimbim2697
  • bimbim2697
@GT Can U show me wht u mean by tht ?

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bimbim2697
  • bimbim2697
Please Im so lost! :(
anonymous
  • anonymous
|dw:1328580546395:dw|
anonymous
  • anonymous
That line is y=2. So, all points below that would be y<2.
anonymous
  • anonymous
|dw:1328580663387:dw|
anonymous
  • anonymous
All those points in that region satisfy the inequality.
bimbim2697
  • bimbim2697
im like slowly getting it hoe eud u find y
anonymous
  • anonymous
|dw:1328580825246:dw|
anonymous
  • anonymous
That line is y=x. So, for y
anonymous
  • anonymous
|dw:1328580896828:dw|
bimbim2697
  • bimbim2697
@gt how do i determine of the ordered pair is a solution of the linear inequality 7x+2y>-5,(-1,1) x-y<=3, (2,-1)
anonymous
  • anonymous
replace x by -1 and y by 1 and see if it works
anonymous
  • anonymous
\[7\times (-1)+2\times 1=-7+2=-5\] and now we have to be careful because \[-5<-5\] is not true, so no for the first one
anonymous
  • anonymous
second one replace x by 2, y by -1 and get \[2-(-1)\leq 3\] \[3\leq 3\] and that one is true
bimbim2697
  • bimbim2697
What abt the last one ?
anonymous
  • anonymous
that was the last one. that was \[x-y\leq 3\] for \[(2,-1)\]
anonymous
  • anonymous
answer is yes, i does satisfy that inequality
bimbim2697
  • bimbim2697
oh my first set of questions
bimbim2697
  • bimbim2697
y>3x-4 x+y<-3 x-2y>-1 x =>-4 y<2 y

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