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anonymous
 4 years ago
limit of x> infinity
(x + 2)/sqrt(49x^2 + 1)
anonymous
 4 years ago
limit of x> infinity (x + 2)/sqrt(49x^2 + 1)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0forget the 1 under the square root, the 2 in the numerator, and compute \[\frac{x}{\sqrt{49x^2}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty}\frac{(x+2)}{\sqrt{49x ^{2}+1}}\]\[\lim_{x \rightarrow \infty}\frac{\frac{(x+2)}{x}}{\frac{\sqrt{49x ^{2}+1}}{x}}\]\[\lim_{x \rightarrow \infty}\frac{1+\frac{2}{x}}{\sqrt{49+\frac{1}{x ^{2}}}}\]Reaplace the value infinite:\[\frac{1+0}{\sqrt{49+ 0}}\]\[\frac{1}{7}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that will work for sure, but \[\frac{x}{\sqrt{49x^2}}=\frac{1}{7}\] is somewhat quicker
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