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anonymous

  • 4 years ago

Exponential Growth problem...see attached. I got r = .014384, but the answer key says otherwise.

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  1. anonymous
    • 4 years ago
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    i got a cartoon and some cars when clicking on the link

  2. anonymous
    • 4 years ago
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    http://i40.tinypic.com/w0nqyb.jpg

  3. anonymous
    • 4 years ago
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    How's that?

  4. anonymous
    • 4 years ago
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    ok what is "growth constant?" are you supposed to find k in \[Ae^kt\]?

  5. anonymous
    • 4 years ago
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    i meant \[P(t)=A_0 e^{kt}\]

  6. anonymous
    • 4 years ago
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    that's the formula that I used. I used 4.5 for A0

  7. anonymous
    • 4 years ago
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    20 for time since 1980

  8. anonymous
    • 4 years ago
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    6 on the other side

  9. anonymous
    • 4 years ago
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    ok so you should be solving \[6=4.5e^{20k}\] for k

  10. anonymous
    • 4 years ago
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    yes

  11. anonymous
    • 4 years ago
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    I divided both sides by 4.5, then took the natural log of both sides

  12. anonymous
    • 4 years ago
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    I got .28768 = 20 k

  13. anonymous
    • 4 years ago
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    \[\frac{6}{4.5}=e^{20k}\] \[\frac{4}{3}=e^{20k}\] \[20k=\ln(\frac{4}{3})\] \[k=\frac{\ln(\frac{4}{3})}{20}\]

  14. anonymous
    • 4 years ago
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    solving for k, I got .014384

  15. anonymous
    • 4 years ago
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    Answer key says: .02310

  16. anonymous
    • 4 years ago
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    \[k=0.0143841\] rounded

  17. anonymous
    • 4 years ago
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    i get what you got

  18. anonymous
    • 4 years ago
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    I don't know where they are getting this answer from in the key....must be a typo?

  19. anonymous
    • 4 years ago
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    answer key is messed up

  20. anonymous
    • 4 years ago
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    lol, thanks for checking with me

  21. anonymous
    • 4 years ago
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    it happens. problems written my cadres of bored graduate students for extra cash, can easily be a mistake

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