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precal

  • 4 years ago

Find y' y=sinx + (4cosx)/x

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  1. precal
    • 4 years ago
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    Do I do quotient rule for the 2nd part?

  2. anonymous
    • 4 years ago
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    yes

  3. anonymous
    • 4 years ago
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    do u want me to show u?

  4. precal
    • 4 years ago
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    Let's see if I know how

  5. anonymous
    • 4 years ago
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    lol ok so u do it and then come back with the answer

  6. precal
    • 4 years ago
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    y'=cosx + x(-4sinx)-(4cosx)(1) y'=cosx-4sinx-4cosx y'=-3cosx - 4sinx

  7. precal
    • 4 years ago
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    did I do it right?

  8. anonymous
    • 4 years ago
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    no

  9. precal
    • 4 years ago
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    I forgot x^2 under it

  10. anonymous
    • 4 years ago
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    yes

  11. precal
    • 4 years ago
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    ok I will do it again

  12. anonymous
    • 4 years ago
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    but otherwise it is basically correct

  13. precal
    • 4 years ago
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    y'=cosx+ (-4sinx-4cosx)/x^2

  14. anonymous
    • 4 years ago
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    umm no you it shld be -4xsinx

  15. anonymous
    • 4 years ago
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    u included it the first time around

  16. precal
    • 4 years ago
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    you are so right y'=cosx+ (- 4xsinx-4cosx)/x^2

  17. anonymous
    • 4 years ago
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    ok ya this is fine

  18. anonymous
    • 4 years ago
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    you cld techinically factor out a -4

  19. anonymous
    • 4 years ago
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    but it isnt necessary. only if u want ur answer to look a lil neater

  20. precal
    • 4 years ago
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    what should my final answer look like? I am always interested in making it look neater.

  21. anonymous
    • 4 years ago
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    |dw:1328585019835:dw|

  22. precal
    • 4 years ago
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    thanks

  23. anonymous
    • 4 years ago
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    oh something is wrong with this drawing shreks

  24. anonymous
    • 4 years ago
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    but whtvr u get the point i think

  25. anonymous
    • 4 years ago
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    umm what level math r u in?

  26. precal
    • 4 years ago
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    I am past graduate work in mathematics. I do this for fun!

  27. anonymous
    • 4 years ago
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    lol r u serious???? cuz last time u helped with a hard questionand this is so simple so i thought i maybe was confusig u with someone else

  28. precal
    • 4 years ago
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    |dw:1328586020836:dw| I think you dropped a sign.

  29. anonymous
    • 4 years ago
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    lol yes

  30. precal
    • 4 years ago
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    No, I am very rusty in calculus so I am trying to challenge myself with calculus. I am pretty good in Algebra, Geometry, Precal, and so forth. But Calculus I am rusty.

  31. anonymous
    • 4 years ago
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    oh u helped me in linear algebra

  32. precal
    • 4 years ago
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    Ok if I can. It has been a while since I have seen Linear Algebra. That was one of my favorite courses. I am also, very rusty in proofs.

  33. precal
    • 4 years ago
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    There are alot of very smart people here. Post your problem separately in case, I can not help you. That way someone might help along the way.

  34. anonymous
    • 4 years ago
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    no i dont need help but u have helped me :D

  35. precal
    • 4 years ago
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    anytime :)

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