Find y'
y=sinx + (4cosx)/x

- precal

Find y'
y=sinx + (4cosx)/x

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- precal

Do I do quotient rule for the 2nd part?

- anonymous

yes

- anonymous

do u want me to show u?

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## More answers

- precal

Let's see if I know how

- anonymous

lol ok so u do it and then come back with the answer

- precal

y'=cosx + x(-4sinx)-(4cosx)(1)
y'=cosx-4sinx-4cosx
y'=-3cosx - 4sinx

- precal

did I do it right?

- anonymous

no

- precal

I forgot x^2 under it

- anonymous

yes

- precal

ok I will do it again

- anonymous

but otherwise it is basically correct

- precal

y'=cosx+ (-4sinx-4cosx)/x^2

- anonymous

umm no you it shld be -4xsinx

- anonymous

u included it the first time around

- precal

you are so right
y'=cosx+ (- 4xsinx-4cosx)/x^2

- anonymous

ok ya this is fine

- anonymous

you cld techinically factor out a -4

- anonymous

but it isnt necessary. only if u want ur answer to look a lil neater

- precal

what should my final answer look like? I am always interested in making it look neater.

- anonymous

|dw:1328585019835:dw|

- precal

thanks

- anonymous

oh something is wrong with this drawing shreks

- anonymous

but whtvr u get the point i think

- anonymous

umm what level math r u in?

- precal

I am past graduate work in mathematics. I do this for fun!

- anonymous

lol r u serious???? cuz last time u helped with a hard questionand this is so simple so i thought i maybe was confusig u with someone else

- precal

|dw:1328586020836:dw|
I think you dropped a sign.

- anonymous

lol yes

- precal

No, I am very rusty in calculus so I am trying to challenge myself with calculus. I am pretty good in Algebra, Geometry, Precal, and so forth. But Calculus I am rusty.

- anonymous

oh u helped me in linear algebra

- precal

Ok if I can. It has been a while since I have seen Linear Algebra. That was one of my favorite courses. I am also, very rusty in proofs.

- precal

There are alot of very smart people here. Post your problem separately in case, I can not help you. That way someone might help along the way.

- anonymous

no i dont need help but u have helped me :D

- precal

anytime :)

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