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anonymous
 4 years ago
I'm starting to forget this factoring thing, where the coefficient is not 1. can some one please go in details and explain?
anonymous
 4 years ago
I'm starting to forget this factoring thing, where the coefficient is not 1. can some one please go in details and explain?

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precal
 4 years ago
Best ResponseYou've already chosen the best response.2I will show you a trick that works

precal
 4 years ago
Best ResponseYou've already chosen the best response.2Take the 4 and multiply it to the 15 and get 60 rewrite as \[x^216x+60\] Factor (x6)(x10) since you took out the 4 by multiplying it, you must return it by dividing it (x(6/4))(x(10/4)) Whatever number you remove, you must return in (x(3/2))(x(5/2)) I just reduced the fractions since 3/2 is 1.5 I need to move the 2 to the front of the x since 5/2 is 2.5 I need to move the 2 to the front of the x (2x3)(2x5) You can check it by multiplying it out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0precal thank you very much.. you sir are a life sever

precal
 4 years ago
Best ResponseYou've already chosen the best response.2I love to use this trick, it always works. Don't forget to divide the number back in...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what about having big numbers please

precal
 4 years ago
Best ResponseYou've already chosen the best response.2still works but if you have big numbers, you can always factor a number out example 4x^2+2x+2 or act like I actually used big numbers 2(2x^2+1x+1) then do the trick inside
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