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anonymous

  • 4 years ago

X^2y'=xy-y^2

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  1. anonymous
    • 4 years ago
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    What r we solving for?

  2. anonymous
    • 4 years ago
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    for some reason i cant simplify x^2(xv'+v)=xv-v^2 into v= the differential eq

  3. anonymous
    • 4 years ago
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    I got: x^3+x^2-x+v=0

  4. anonymous
    • 4 years ago
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    idk if it's right or if I even did it right but I tried.

  5. anonymous
    • 4 years ago
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    Here is a detailed explanation of the solution x and y. Y is the first picture.

  6. anonymous
    • 4 years ago
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    the answer is y=x/((ln (x )+c) i got it i made a stupid substitution for y using y=v when it should y=vx which yields a simple factor and simplification

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spraguer (Moderator)
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