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anonymous

  • 4 years ago

Given f (x) = 7x^2 + 4x - 13, A = sum of roots of f (x) = 0, B = product of roots of f (x) = 0, find ( A + B)^2

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  1. anonymous
    • 4 years ago
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    Won't factor, use quadratic formula

  2. anonymous
    • 4 years ago
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    not to butt in but you can find the sum of the roots and the produce of the roots without finding the roots

  3. anonymous
    • 4 years ago
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    Alright then, the floor is yours lol

  4. anonymous
    • 4 years ago
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    you can also prove those formulas using the quadratic formula, but sum of roots of a quadratic \[ax^2+bx+c=0\] \[r_1+r_2=-\frac{b}{a}\] produce is \[r_1r_2=\frac{c}{a}\]

  5. anonymous
    • 4 years ago
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    *product

  6. anonymous
    • 4 years ago
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    The answer is 289/49. Could you please show me the steps?

  7. anonymous
    • 4 years ago
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    product of the roots, according to satellite's formula is -13/7

  8. anonymous
    • 4 years ago
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    sum is -4/7

  9. anonymous
    • 4 years ago
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    \[(-\frac{13}{7}-\frac{4}{7})^2=(-\frac{17}{7})^2=\frac{289}{49}\]

  10. anonymous
    • 4 years ago
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    Thank you so much

  11. anonymous
    • 4 years ago
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    could you explain how did you get the A .

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spraguer (Moderator)
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