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anonymous
 4 years ago
\[\int_{2}^{2} x~e^{i~p~x}dx\]
anonymous
 4 years ago
\[\int_{2}^{2} x~e^{i~p~x}dx\]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[u=x\]\[du=dx\]\[dv=e ^{ipx}dx\]\[v=\frac{e ^{ipx}}{ip}\]\[\int\limits_{}^{}udv=uv\int\limits_{}^{}vdu\]\[=x(\frac{e ^{ipx}}{ip})\int\limits_{}^{}(\frac{e ^{ipx}}{ip})dx\]can you continue?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, just wanted to make sure i did it right, the first term becomes 2icos(p)/p right? and the 2nd becomes 2isin(p)/p^2 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wrote down the limits of integration on the question wrgon, they're from 1 to 1.
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