## anonymous 4 years ago $\int_{-2}^{2} x~e^{-i~p~x}dx$

1. anonymous

p is constant?

2. anonymous

yes

3. anonymous

$u=x$$du=dx$$dv=e ^{-ipx}dx$$v=\frac{-e ^{-ipx}}{ip}$$\int\limits_{}^{}udv=uv-\int\limits_{}^{}vdu$$=x(\frac{-e ^{-ipx}}{ip})-\int\limits_{}^{}(\frac{-e ^{-ipx}}{ip})dx$can you continue?

4. anonymous

yeah, just wanted to make sure i did it right, the first term becomes 2icos(p)/p right? and the 2nd becomes 2isin(p)/p^2 ?

5. anonymous

Wrote down the limits of integration on the question wrgon, they're from -1 to 1.