anonymous
  • anonymous
consider the following quadratic function...k(x)=(x-6)..find the vertex of this function
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
that's not a quadratic function
anonymous
  • anonymous
is (x-6) raised to the 2nd power?
anonymous
  • anonymous
no...it's not on the problem...that's how it's worded

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anonymous
  • anonymous
k(x)=x-6 is a line
anonymous
  • anonymous
I have the answer..I just don't understand how to do the problem...the answer is (6,0)
anonymous
  • anonymous
Well, I'm going to assume it is k(x)=(x-6)^2 Expand: x^2-12x+36 The vertex of a parabola written in the for ax^2+bx+c is: \[(-\frac{b}{2a},f(-\frac{b}{2a})\] \[(\frac{12}{2},f(\frac{12}{2}))=(6,f(6))=(6,0)\]
anonymous
  • anonymous
looks good....worked it out..now quick question...why is f(6)=0?
anonymous
  • anonymous
f(6)=6^2-12(6)+36=36-72+36=0
anonymous
  • anonymous
or in the original form, f(x)=(x-6)^2 f(6)=(6-6)^2=0^2=0
anonymous
  • anonymous
makes sense now thank you

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