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anonymous
 4 years ago
Find the derivative. (Chain Rule)
f(y) = 4 / (4y^2)^4
anonymous
 4 years ago
Find the derivative. (Chain Rule) f(y) = 4 / (4y^2)^4

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dumbcow
 4 years ago
Best ResponseYou've already chosen the best response.3set u = 4y^2 du = 2y f(u) = 4/u^4 = 4u^4 f'(u) = 16u^5 = 16/u^5 f'(y) = f'(u)*du f'(y) = [16/(4y^2)^5]*(2y) f'(y) = 32y/(4y^2)^5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f(y)=4(4y^2)^{4}\] \[f'(y)=16(4y^2)^{5}*(2y)=\frac{32y}{(4y^2)^5}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The back of the textbook with answers says that its 24y/(4y^2)^5 ...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@ Kevin rick is correct,it must be a misprint in your textbook.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think you guys are correct. I sure hope that it's a misprint. :) Thank you!
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