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anonymous

  • 4 years ago

The doorsill of a campus building is h = 5 feet above ground level. To allow wheelchair access, the steps in front of the door are to be replaced by a straight ramp with constant slope 1/10, as shown in the figure. How long must the ramp be? [The answer is not 50 feet.]...help please :)

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  1. anonymous
    • 4 years ago
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    |dw:1328596978457:dw| \[\frac{1}{10}=\frac{5}{50}\] \[x=\sqrt{50^2+5^2}=5\sqrt{101} ft \approx 50.2494 ft\]

  2. anonymous
    • 4 years ago
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    thank you so much!!!

  3. anonymous
    • 4 years ago
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    you're welcome

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