## anonymous 4 years ago The doorsill of a campus building is h = 5 feet above ground level. To allow wheelchair access, the steps in front of the door are to be replaced by a straight ramp with constant slope 1/10, as shown in the figure. How long must the ramp be? [The answer is not 50 feet.]...help please :)

1. anonymous

|dw:1328596978457:dw| $\frac{1}{10}=\frac{5}{50}$ $x=\sqrt{50^2+5^2}=5\sqrt{101} ft \approx 50.2494 ft$

2. anonymous

thank you so much!!!

3. anonymous

you're welcome