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anonymous
 4 years ago
find the equation of the line through the points (6,7) (2, 1)
anonymous
 4 years ago
find the equation of the line through the points (6,7) (2, 1)

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0find the gradient 1st rise/run or\[m =(y _{2} y _{1})/(x _{2}  x _{1})\] so ( 1  7)/(26) = 8/4 =2 the gradient is m = 2 use the point gradient formula with either point... \[y  y _{1}=m(x  x _{1})\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that what i did but have have to get it equal to y which im having trouble doing...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have y7=2 (x+6) so far...

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0add 7 to both sides... and expand the brackets

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sooo y=2(x+6+7) ? i put in y=2(x+13) and it was wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is still coming up as wrong :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[y=mx+b \] Use your two points (ordered pairs) to find the slope (rise over run or the difference of the Ys over the differences over the Xs). \[(17)/(26)\] You can simplify this to 2. This gives you...\[y=2x+b\]. B is your Yintercept (where the line crosses the Yaxis, or when X is zero). To solve for B with a known point and slope, fillin all the known variables and solve for B.\[1=2*2+b\]\[1=4+b\]\[b=5\] Now you have the your Yintercept. Your equation should look like this.\[y=2x5\]
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