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anonymous
 4 years ago
How do you find an equation for the line satisfying the given conditions.
Through (3, 3) and parallel to 3x  4y = 7 ??
anonymous
 4 years ago
How do you find an equation for the line satisfying the given conditions. Through (3, 3) and parallel to 3x  4y = 7 ??

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0write the equation of the line in point slope form y = mx + b or y = 3/4 x  7/4 parallel lines have the same gradient... so use the gradient of this line and the point slope formula.. with the given point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let the equation of the line be y=mx+c m=3/4 Applying the given point and m 3=3/4*3+c c=3/4 the eqn is y=3/4x+3/4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0First isolate y: 4y=3x+7 y=(3/4)x7/4 The slope is 3/4. Our parallel line will have this slope as well. Pointslope form: \[yy1=m(xx1)\] \[y3=\frac{3}{4}(x3)\] slopeintercept form: \[y=mx+b\] \[y=\frac{3}{4}x+\frac{3}{4}\]
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