## anonymous 4 years ago How do you find an equation for the line satisfying the given conditions. Through (3, 3) and parallel to 3x - 4y = 7 ??

1. campbell_st

write the equation of the line in point slope form y = mx + b or y = 3/4 x - 7/4 parallel lines have the same gradient... so use the gradient of this line and the point slope formula.. with the given point

2. anonymous

Let the equation of the line be y=mx+c m=3/4 Applying the given point and m 3=3/4*3+c c=3/4 the eqn is y=3/4x+3/4

3. anonymous

First isolate y: -4y=-3x+7 y=(3/4)x-7/4 The slope is 3/4. Our parallel line will have this slope as well. Point-slope form: $y-y1=m(x-x1)$ $y-3=\frac{3}{4}(x-3)$ slope-intercept form: $y=mx+b$ $y=\frac{3}{4}x+\frac{3}{4}$