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anonymous

  • 4 years ago

anyone know how to graph 4x-5y=12 ? i got it to y=12-4x-5 but idk if thats even right...

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  1. anonymous
    • 4 years ago
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    y=4/5x-12/5

  2. campbell_st
    • 4 years ago
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    use a table of values and substitute them into the equation try x = 0 x = 1 and x = 2..... you'll get a corresponding y value for each x.... plot the points and then draw a line through the points... or find the x intercept by letting y = 0 and solving...y intercept let x = 0 and solve for y

  3. anonymous
    • 4 years ago
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    yeah i still dont understand how to graph it that way...

  4. anonymous
    • 4 years ago
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    Ok first you have to get the y alone so subtract the x. -5y = -4x + 12 Y cannot be positive, so you must divide/multiply by -1. 5y = 4x - 12 Y must be alone, you need to get rid of the five, so divide everything by 5. Y= 4/5x - 12/5 Your slope is rise 4 run 5, and you need to graph at the point -12/5 on the Y axis, so thats -2.4

  5. anonymous
    • 4 years ago
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    thank you for explaining it :)

  6. anonymous
    • 4 years ago
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    Meant Y must be positive, wups.

  7. anonymous
    • 4 years ago
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    wait so what are the points? im confused now

  8. anonymous
    • 4 years ago
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    You go down to -12/5, or -2.4 on the Y axis. Then you use your slope to continue the line, going up 4 then over 5 times, and repeating. Get it?

  9. anonymous
    • 4 years ago
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    The -12/5 is the point you start graphing your line at, then you use the slope to start the line from there.

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