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  • 4 years ago

In Standing Waves, The condition for an Antinode is (n+1/2)lamda When considering a pipe open at both the ends, Antinode is formed at both the ends, Then why is L = nLamda/2 ? Shouldnt it be L = (n+1/2)lamda/2 ?

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  1. Mani_Jha
    • 4 years ago
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    The condition for an antinode is \[x=(2n+1)\lambda/4\]. Check it and for node is \[x=(n+1)\lambda/2\]. If you r considering sound waves, nodes will be formed at the ends, and the same equations hold. The equation \[L=n \lambda/2\] is a consequence of the ends being nodal points(u can see it in 8.03 Vibrations and Waves).

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