## anonymous 4 years ago In Standing Waves, The condition for an Antinode is (n+1/2)lamda When considering a pipe open at both the ends, Antinode is formed at both the ends, Then why is L = nLamda/2 ? Shouldnt it be L = (n+1/2)lamda/2 ?

The condition for an antinode is $x=(2n+1)\lambda/4$. Check it and for node is $x=(n+1)\lambda/2$. If you r considering sound waves, nodes will be formed at the ends, and the same equations hold. The equation $L=n \lambda/2$ is a consequence of the ends being nodal points(u can see it in 8.03 Vibrations and Waves).