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anonymous

  • 4 years ago

O is the centre of large circle. Show that QS=QR. The diagram is attached below.

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  1. anonymous
    • 4 years ago
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  2. dumbcow
    • 4 years ago
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    not sure, thats all the info given

  3. dumbcow
    • 4 years ago
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    oh i see now if you move PR so it goes through center, it shows that both QR and QS are same length as radius

  4. campbell_st
    • 4 years ago
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    produce the line QS to the circumference of the of circle centre 0. Join XR .... Join PS... so you have 2 triangles... in the large circle... |dw:1328600319070:dw| you now have 2 triangles.... RQX and PQS you need to prove congruency start with angle XQR = angle PQS ( vertically opposite) XR = PS ( equal chords subtend angles).... I think that is the statement Angle XRQ = Angle PSQ ( equal angles subtended on the arc PX) I think this proves congruency by Angle Angle Side test... so therefore QR = QS corresponding sides in congruent triangles.. Check my proof as its ages since I did circle geometry

  5. anonymous
    • 4 years ago
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    Thank you so much! :)

  6. anonymous
    • 4 years ago
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    Great job campbell!

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