anonymous
  • anonymous
Given that x and y are positive integers, solve x^y = y^x
Mathematics
jamiebookeater
  • jamiebookeater
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dumbcow
  • dumbcow
can i do the obvious one...x=1, y=1
anonymous
  • anonymous
You have to find all the solutions.Of course 1 is obvious.
anonymous
  • anonymous
Wouldn't all solutions be on a line of y=x?

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dumbcow
  • dumbcow
wait can x=y, if so then any number would work
anonymous
  • anonymous
4 and 2 is another.
anonymous
  • anonymous
x=y is one . What about x>y?
dumbcow
  • dumbcow
the only solution is 4 and 2, at least for numbers up to 1000

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