anonymous
  • anonymous
a particle is projected with velocity 9m/s up a line of greatest slope of a smooth plane inclined at an angle a to the horizontal where sin a=4/7. find the speed of the particle when it has travelled 5m up the plane.
Physics
schrodinger
  • schrodinger
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AravindG
  • AravindG
u get a by taking arcsin 4/7
anonymous
  • anonymous
then?
AravindG
  • AravindG
srry i gota do my problems bye i am sure smone else will help

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AravindG
  • AravindG
wel i'll giv u hint
AravindG
  • AravindG
use s=ut+1/2 at^2 for horizontal component and get time substitute this time in any other eqn to get ur v
anonymous
  • anonymous
i get the answer 11.71m/s using formula s=vt-1/2at^2. is it correct?
anonymous
  • anonymous
how?
anonymous
  • anonymous
use equation v^2=u^2+2as
anonymous
  • anonymous
what is a?
anonymous
  • anonymous
a=-g(sin a)
anonymous
  • anonymous
\[-mg \sin \Theta =ma\] sin theta=4.7
anonymous
  • anonymous
so our formula is matched but final a isn't
anonymous
  • anonymous
how could??
anonymous
  • anonymous
a=-g(sin a) & \[v=\sqrt{(v _{0}^{2}+2as)}\]
anonymous
  • anonymous
then,u get same answer as me or not?
anonymous
  • anonymous
i distracted no .never mind i'll find it
anonymous
  • anonymous
unbelievable..
anonymous
  • anonymous
i think 4.99 is correct hence particles velocity ought be decreased
anonymous
  • anonymous
okey. thanx a lot.
anonymous
  • anonymous
ur wellcome friend
AravindG
  • AravindG
no medals??

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