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anonymous
 4 years ago
Given that sin θ = sqrt(3)/7 and tan θ < 0, find sec θ and tan θ.
anonymous
 4 years ago
Given that sin θ = sqrt(3)/7 and tan θ < 0, find sec θ and tan θ.

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y2o2
 4 years ago
Best ResponseYou've already chosen the best response.1θ is in the second quad. so you can use sin^1 function or you can use Pythagoras theorem and SOH CAH TOA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so x^2 + y^2 = r^2 x^2 + sqrt(3)^2 = 7^2 x^2 + 3 = 49 x^2 = 46 x = sqrt(46) right?

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.1yes you got the adjacent right. so now you can get the cos and the tan but remember that both of them will be ve

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So Sec θ =  7sqrt(46)/46 Tan θ =  sqrt(138)/46

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cool, thanks. I wasn't sure if I could reduce it further.
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