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AJTurnbull
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a car is traveling in a straight line and decelerating at a constant rate. after 3.2 s it traveled 88m and slowed to a speed of 17m/s what was the initial speed of the car?
 2 years ago
 2 years ago
AJTurnbull Group Title
a car is traveling in a straight line and decelerating at a constant rate. after 3.2 s it traveled 88m and slowed to a speed of 17m/s what was the initial speed of the car?
 2 years ago
 2 years ago

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nikvist Group TitleBest ResponseYou've already chosen the best response.0
\[t=3.2s\quad,\quad s=88m\quad,\quad v=17m/s\]\[v=v_0at\quad\Rightarrow\quad a=\frac{v_0v}{t}\]\[v^2=v_0^22as=v_0^22\frac{v_0v}{t}s=v_0^2\frac{2s}{t}v_0+\frac{2s}{t}v\]\[v_0^2\frac{2s}{t}v_0+\frac{2s}{t}vv^2=0\]\[v_0=\frac{\frac{2s}{t}\pm\sqrt{\left(\frac{2s}{t}\right)^24\left(\frac{2s}{t}vv^2\right)}}{2}=\]\[=\frac{s}{t}\pm\sqrt{\left(\frac{s}{t}\right)^2\frac{2s}{t}v+v^2}=\frac{s}{t}\pm\sqrt{\left(\frac{s}{t}v\right)^2}=\]\[=\frac{s}{t}\pm\left(\frac{s}{t}v\right)\quad\mbox{(only sign +)}\]\[v_0=\frac{2s}{t}v=38m/s\]
 2 years ago

shubham Group TitleBest ResponseYou've already chosen the best response.2
OR Use this equation of motion S = {(u+v)/2}t 88m = {(u+17)/2}3.2 u=5513 = 38m/s
 2 years ago

AJTurnbull Group TitleBest ResponseYou've already chosen the best response.0
how did you get a?
 2 years ago

shubham Group TitleBest ResponseYou've already chosen the best response.2
For constant accelarations, velocity is linear function of time and hence you can assume mean of initial and final velocities to be the average velocity. So, you don't need a actually.
 2 years ago

AJTurnbull Group TitleBest ResponseYou've already chosen the best response.0
oh that makes it easy been trying to figure that out all night
 2 years ago
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