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anonymous

  • 4 years ago

OK gonna need some help... Don't remember this! Find sin 540° + 4(tan150°)(cot120°)

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  1. anonymous
    • 4 years ago
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    sin 540 = sin 180 = 0 tan 150 = -1 / sqrt(3) cot 120 = -1 / sqrt(3)

  2. anonymous
    • 4 years ago
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    \[0 + 4 \times ( {-1 \over \sqrt{3}} \times {-1 \over \sqrt{3}} )\] \[4 \times { { -1 \times -1 } \over \sqrt3 \times \sqrt3 }\] \[4 \times { 1 \over 3 } = { 4 \over 3}\]

  3. anonymous
    • 4 years ago
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    Is that how you do it? crazy I would have never got that in a million years.

  4. anonymous
    • 4 years ago
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    Simple, i calculate the results for the 3 different goniometric expressions, then feed them into the given formula. Remember, with math, it's not enough to remember something only for a test. You'll need everything you learn in subsequent tests.

  5. anonymous
    • 4 years ago
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    thought tan = 150 would be 30 degrees which is sqrt(3)/3 and cot = 120 would be 60 degrees which is sqrt(3)/3

  6. anonymous
    • 4 years ago
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    wouldn't they both be negative as well?

  7. anonymous
    • 4 years ago
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    yep, they are, but a negative times a negative is a positive

  8. anonymous
    • 4 years ago
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    since sqrt(3)/3 x sqrt(3)/3 = 3/9 and 0 + 4(3/9) = 7/9? So it would be 7/9

  9. Mertsj
    • 4 years ago
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    \[\frac{4}{1}\times\frac{3}{9}=\frac{12}{9}=\frac{4}{3}\]

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