OK gonna need some help... Don't remember this! Find sin 540° + 4(tan150°)(cot120°)

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OK gonna need some help... Don't remember this! Find sin 540° + 4(tan150°)(cot120°)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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sin 540 = sin 180 = 0 tan 150 = -1 / sqrt(3) cot 120 = -1 / sqrt(3)
\[0 + 4 \times ( {-1 \over \sqrt{3}} \times {-1 \over \sqrt{3}} )\] \[4 \times { { -1 \times -1 } \over \sqrt3 \times \sqrt3 }\] \[4 \times { 1 \over 3 } = { 4 \over 3}\]
Is that how you do it? crazy I would have never got that in a million years.

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Simple, i calculate the results for the 3 different goniometric expressions, then feed them into the given formula. Remember, with math, it's not enough to remember something only for a test. You'll need everything you learn in subsequent tests.
thought tan = 150 would be 30 degrees which is sqrt(3)/3 and cot = 120 would be 60 degrees which is sqrt(3)/3
wouldn't they both be negative as well?
yep, they are, but a negative times a negative is a positive
since sqrt(3)/3 x sqrt(3)/3 = 3/9 and 0 + 4(3/9) = 7/9? So it would be 7/9
\[\frac{4}{1}\times\frac{3}{9}=\frac{12}{9}=\frac{4}{3}\]

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