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shivamsinha

  • 2 years ago

plzz help me now....... if cosy=xcos(a+y) theprove that dy/dx=(cos^2 (a+y))/sina

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  1. shivamsinha
    • 2 years ago
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    i jst dbtknw ...y i g8 stuck wit simple sums....:(

  2. dumbcow
    • 2 years ago
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    using implicit differentiation: \[\frac{dy}{dx} = \frac{\cos(a+y)}{x \sin(a+y)-\sin(y)}\]

  3. dumbcow
    • 2 years ago
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    then im guessing use sum of angles formula

  4. dumbcow
    • 2 years ago
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    sin(a+y) = sin(a)cos(y) + sin(y)cos(a)

  5. shivamsinha
    • 2 years ago
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    \[shouldnt ittt be -\sin(y) dy/dx =-\sin(a+y)x+coas(a+y)\]

  6. dumbcow
    • 2 years ago
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    i don't know if im helping :| there should be a dy/dx with the -sin(a+y)x term

  7. shivamsinha
    • 2 years ago
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    ywesssss it shud b sry it din write

  8. shivamsinha
    • 2 years ago
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    pellet....yes u r write....mdumb :P

  9. shivamsinha
    • 2 years ago
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    *pellettt

  10. shivamsinha
    • 2 years ago
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    *pelletttt

  11. shivamsinha
    • 2 years ago
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    ***crap...

  12. shivamsinha
    • 2 years ago
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    censorship even here??? :P

  13. dumbcow
    • 2 years ago
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    haha from here though im not sure where to go, they don;t have an x in their answer ...i don't see how the x cancels anywhere

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