i have some algebra equations that i have done. can you check them? (i will post them soon).

- hihi67

i have some algebra equations that i have done. can you check them? (i will post them soon).

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- hihi67

a) k/3 + k/2 =

- hihi67

b) 4/5 x - 1/10 x

- hihi67

c) 3/8 z - 1/4 z + 1/2 z

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- hihi67

d) s/5 - s/3 + s

- hihi67

e) 1 1/2 m - 3/4m + m/8

- hihi67

and.....

- hihi67

f) -4a/5 + 1/10a - 3a

- hihi67

tell me what answers you get, and then i will see if i have the same. pleasee....?

- agreene

a) \[\frac{5k}6\]
b) \[\frac7{10x}\]
c) \[\frac5{8z}\]
d) \[\frac{13s}{15}\]
e) \[\frac{m}{8}-\frac{1}{4m}\]
f) \[\frac1{10a}-\frac{19a}5\]

- hihi67

okay... well for a b and c i have the same. for d i have - 17/15s. for e i have 6/8m. for f i have - 3 and 9/10a

- hihi67

this is how i figured it out. d:

- agreene

from d down it was a bit hard to know what the question was--since you didn't use parenthesis.

- hihi67

no () in book either.

- hihi67

ust a min.

- agreene

d could have been:
\[\frac{s}5 - \frac{s}3 + s\] which is what i assumed, or
\[\frac{s}5-\frac{s}{3+s}\] which would be a harder problem, lol

- hihi67

\[s/5 - s/3 + s : \space \space \space \space \space \space \space \space \space s-5-s/3 = 3s/15 - 5s/15 \space \space \space that equals -2s/15 \space \space \space \space \space -2s/15 + s = \]

- hihi67

thats d

- hihi67

dang cant see it.

- hihi67

never mind...

- hihi67

bye thanks

- agreene

lol dont give up so quickly :P

- hihi67

ooooh I KNOW!

- hihi67

stupid "order of operations"

- hihi67

yep, thanks! you really actually did help a lot!!!

- agreene

for d:
I find it easier to start by factoring out the variables (makes it easier for me to see):
s/5 - s/3 +s
\[\frac15(s) - \frac13(s)+ s\]
combine your fractions:
\[-\frac2{15}(s)+s\]
combine those fractions (convert the +s to +15s/15 so its the same denominator)
\[\frac{15}{15}(s) - \frac2{15}(s) = \frac{15-2}{15}(s)==\frac{13}{15}(s)\]
or
\[\frac{13s}{15}\]
thats how I like to work these, of course--if your way is easier for you and works, do that!

- hihi67

you are very much a genius. that really helps!!!! you should become my math teacher!

- hihi67

hah

- hihi67

what about for e?

- hihi67

e is 7/8m

- hihi67

because: 1 1/2m is 3/2m and 3/4 m, normal. m/8 = 1/8 times m.
3/2 time m - 3/4 times m is 3/4 times m. 3/4 time m - 1/8 times m is 7/8

- agreene

Its a little bit harder, but:
I'd start by converting that mixed fraction in the front,
1 1/2 = 3/2
so 1 1/(2m) = 3/(2m)
that gives us:
\[\frac3{2m}-\frac3{4m}+\frac{m}8\]
convert that 2m denominator to 4m by multiplying 2/2 through it:
\[\frac6{4m}-\frac3{4m}+\frac{m}8\]
6-3 = 3 so:
\[\frac3{4m}+\frac{m}8\]
although you can simplify this a bit, id leave it there and call that my answer.

- hihi67

okay..

- hihi67

what i dont get, is f) how is -4a/5 + 1/10 a is -7/10a. its -9/10a!!!

- hihi67

i solved it right, but for some reason i keep getting -9/10.

- hihi67

which is sad, cause i should know how to solve that.

- agreene

combining
\[\frac{-4a}5+\frac1{10a}\]
is a bit tricky, in fact in my first answer, i didn't even do it. the reason is the variable is in the numerator of one and the denominator of the other... if you would like to do it, remember you need to multiply through and get the same denominator... in this case:
10a is what we need.
5 is what we have, so we need to multiply through 2a to the fraction on the left:
\[\frac{-4a}{5}*\frac{2a}{2a}+\frac1{10a}\]
\[\frac{-8a^2}{10a}+\frac1{10a}\] now we can combine these two, since they have the same denominator:
\[\frac{1-8a^2}{10a}\]

- hihi67

oh. i just did 5 * 2 is 10. -4a * 2 is 8!

- agreene

yeah this one is a bit more tricky :P

- hihi67

okay. thank!

- hihi67

you

- hihi67

bye now!

Looking for something else?

Not the answer you are looking for? Search for more explanations.