## anonymous 4 years ago if f:A->B be a function and co-domain=range then the function is onto?

1. anonymous

Yes, range (f)=co-domain (f) implies surjection.

2. anonymous

what ffm said

3. anonymous

range is set of all b in codomain such that there is an a in A with $f(a)=b$ if that is equal to the codomain, then it means function is onto (surjective)

4. anonymous

what sat said, in other words every element $$b \in B$$ is the f-image of some element of A.

5. anonymous

NOTE: If co-domain (f) $$\neq$$ range (f) $$\implies$$ Into function.

6. anonymous

@satellite and foolformath please help if u can. Similar matrices represent the same linear transformation. please prove it or send me a link of its prove its urgent....

7. anonymous
8. anonymous

or look at "change of basis" here