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anonymous

  • 4 years ago

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  1. anonymous
    • 4 years ago
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    \[\frac{3+7i}{(2-5i)(1+3i)} \]

  2. anonymous
    • 4 years ago
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    solve as in write in standard form?

  3. anonymous
    • 4 years ago
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    first multiply out in the denominator and get \[\frac{3+7i}{17+i}\]

  4. anonymous
    • 4 years ago
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    then multiply top and bottom by conjugate of the denominator, get \[\frac{3+7i}{17+i}\frac{17-i}{17-i}\] denominator will be \[17^2+1^2=290\] and the numerator will be whatever you get when you multiply

  5. anonymous
    • 4 years ago
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    it is clear how to multiply the two complex numbers? because that is the basic job here

  6. anonymous
    • 4 years ago
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    Yes i think so.

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