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anonymous
 4 years ago
Integrate
anonymous
 4 years ago
Integrate

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{\pi/2} (2(1\sin \theta))^2 d \theta\] I'm getting a negative number for some reason.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0unlikely since it is a perfect square right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah, I took out the 2^2 out and got sin^2 theta 2 sin theta +1. I then used the half angle formula and got 1/2 + 1/2 cos 2 theta 2 sin theta. I then integrated and pluged back the 4 and I got 2 theta + sin 2 theta + 8 cos theta. But that's wrong.

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.0yes, because the function is always positive, so the area must be positive...check if you made some trigonomety mistakes like sin or cos of some ange etc.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first i would write \[4\int (1\sin(x))^2dx\] then \[4\int \sin^2(x)+12\sin(x) dx\] then integrates each piece separately

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nvm, I made a mistake. I should have integrated each piece seperately THanks.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0only annoying part is the first one, but it looks like you got it right. should get \[2x2\sin(x)\cos(x)+4\cos(x)\] as the "anti derivative" oh and add \[2\pi\] at the end
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