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anonymous
 4 years ago
parallel and perpendicular equations for the point (5,10) 2x + 5y 12 = 0
anonymous
 4 years ago
parallel and perpendicular equations for the point (5,10) 2x + 5y 12 = 0

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2parallel have same equation with a difference constat; perps switch up the xy coeffs and negate one; and change the constant too

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2// 2x + 5y + c = 0 ; calibrate with the given point L 5x  2y + c = 0 ; calibrate with given point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if you calculate it out as in slope intercept form, and got y=2/5 = 12/5 perpendicular would just be 5/2+ whatever else?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that was supposed to be + 12/5

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2looks to be a good set up yes

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2slope is 2/5 for parallel \\ slope is 5/2 for perp L

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2then ignore the 12 and use the point fo find a new constant

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2y = 2/5 x + c 10 = 5(2/5) + c 10 = 2 + c 12 = c y = 2/5  12 ..... that worked out kinda cool lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2forgot the "x" in there tho ... bad amistre, bad!! :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2yw :) the perp is the same concept; ad it looks like your competent enough for that one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know math, I just doubt myself. Whenever I get my work back it's always STUPID little mistakes
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