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anonymous

  • 4 years ago

Problems 1F-7bd... Any help?

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  1. anonymous
    • 4 years ago
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    ah.. 1F part 7, b and d....

  2. anonymous
    • 4 years ago
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    |dw:1328638010890:dw|

  3. anonymous
    • 4 years ago
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    yep, part 7, b and d ;)

  4. anonymous
    • 4 years ago
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    okay you there...here we go.

  5. anonymous
    • 4 years ago
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    rewrite the fraction taking the square root to the top and write it in exponential form...

  6. anonymous
    • 4 years ago
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    |dw:1328639351353:dw|

  7. anonymous
    • 4 years ago
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    Now we will use the product rule and chain rule. Remember all terms are constants except for the v's...

  8. anonymous
    • 4 years ago
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    |dw:1328639570597:dw|

  9. anonymous
    • 4 years ago
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    |dw:1328639645281:dw|

  10. anonymous
    • 4 years ago
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    remember m0 is a constant...

  11. anonymous
    • 4 years ago
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    that is it for 7b.

  12. anonymous
    • 4 years ago
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    give me a minute and i'll look at d.

  13. anonymous
    • 4 years ago
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    are you ready for 7 d?

  14. anonymous
    • 4 years ago
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    |dw:1328640240270:dw|

  15. anonymous
    • 4 years ago
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    I'll use quotient rule this time...

  16. anonymous
    • 4 years ago
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    |dw:1328640318517:dw|

  17. anonymous
    • 4 years ago
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    |dw:1328640421756:dw|

  18. anonymous
    • 4 years ago
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    |dw:1328640527665:dw|

  19. anonymous
    • 4 years ago
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    |dw:1328640609299:dw|

  20. anonymous
    • 4 years ago
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    |dw:1328640672395:dw|

  21. anonymous
    • 4 years ago
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    finished....any questions?

  22. anonymous
    • 4 years ago
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    Nope! Thanks a lot again :) Really elucidative. What bothers me is that I can't master this faster way of performing the chain rule, and then I try to name some variables to apply the slow and steady method, which results in further confusion... I'm gonna watch the video lecture again I guess... But I got your method really easily, thanks again!

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