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anonymous
 4 years ago
Problems 1F7bd... Any help?
anonymous
 4 years ago
Problems 1F7bd... Any help?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah.. 1F part 7, b and d....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328638010890:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep, part 7, b and d ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay you there...here we go.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rewrite the fraction taking the square root to the top and write it in exponential form...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328639351353:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now we will use the product rule and chain rule. Remember all terms are constants except for the v's...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328639570597:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328639645281:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0remember m0 is a constant...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0give me a minute and i'll look at d.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you ready for 7 d?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640240270:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'll use quotient rule this time...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640318517:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640421756:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640527665:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640609299:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328640672395:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0finished....any questions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nope! Thanks a lot again :) Really elucidative. What bothers me is that I can't master this faster way of performing the chain rule, and then I try to name some variables to apply the slow and steady method, which results in further confusion... I'm gonna watch the video lecture again I guess... But I got your method really easily, thanks again!
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