anonymous
  • anonymous
Please, have to submit my worksheet tomorrow, need help!!!! Factor the following fractions into two pairs of brackets: 3-p squared- 2p Please please please!!!
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[(3-p+\sqrt{2p})(3-p-\sqrt{2p})\]
anonymous
  • anonymous
If you meant\[(3-p)^2 -2p\]
jhonyy9
  • jhonyy9
i think 3-p^2 -2p = -(p^2 +2p -3)=-(p+3)(p-1)

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anonymous
  • anonymous
no not the WHOLE squared it's just the 3- p squared
anonymous
  • anonymous
3- p2- 2p
anonymous
  • anonymous
This one ugghh |dw:1328678898789:dw|
anonymous
  • anonymous
This one! help me out?
jhonyy9
  • jhonyy9
(3-p)^2 -2p =9-6p+p^2 -2p =9-8p+p^2 = p^2 -8p +9 =(p-(4-sqrt7))(p-(4+sqrt7)) p_1,2=(8+/- sqrt(64-36))/2 =(8+/- sqrt28)/2 =(8+/- 2sqrt7)/2 = =4+/- sqrt7 p^2 -8p +9 =(p-(4-sqrt7))(p-(4+sqrt7))
anonymous
  • anonymous
what is this? :S
jhonyy9
  • jhonyy9
how is your exercise correct ? like 3-p^2 -2p ???
jhonyy9
  • jhonyy9
so than my first answer is right sure
anonymous
  • anonymous
I didnt get a single thing you did there!
jhonyy9
  • jhonyy9
check it my first answer please
jhonyy9
  • jhonyy9
-(p+3)(p-1)
jhonyy9
  • jhonyy9
=-(p^2 +2p -3) = 3 -p^2 -2p
jhonyy9
  • jhonyy9
ok ?
jhonyy9
  • jhonyy9
good luck bye

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