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anonymous

  • 4 years ago

Electric potential. I have posted the questions as a picture. I hope somebody can help me.

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  1. anonymous
    • 4 years ago
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  2. anonymous
    • 4 years ago
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    Could you write down Gauss' Law?

  3. nikvist
    • 4 years ago
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    Electric field for r>a \[E\sim\frac{1}{r^2}\]

  4. anonymous
    • 4 years ago
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    Electric field shall be calculated at all points in the space Calculate charge enclosed by sphere of radius r \[Q=\int\limits_{0}^{r}p(r)4\pi r^2dr\] we find \[Q'=\frac{Q}{a}r\] nor apply guass's law for spherical symmetry \[E=\frac{Qr}{4\pi r^2a \epsilon_0}\] now do this \[V=-\int\limits_{r}^{\infty}Edr\]

  5. anonymous
    • 4 years ago
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    There are a few changes You must see through the now

  6. anonymous
    • 4 years ago
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    Feel'in lazy to type

  7. anonymous
    • 4 years ago
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    Above relation for E is for 0<r<a for r>a \[E=\frac{Q}{4\pi \epsilon_0r^2}\]

  8. anonymous
    • 4 years ago
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    Now potential \[Q=-\frac{Q}{4\pi \epsilon_0r}\] for r>a 0<r<a \[V(r)=-\frac{Q}{4\pi \epsilon_oa}+\frac{Q}{4\pi a \epsilon_o}\ln(\frac{a}{r})\]

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spraguer (Moderator)
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