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anonymous

  • 4 years ago

need to find m so that y=mx+5 has a common intersection point with y=7x+43 and y=8x+53

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  1. anonymous
    • 4 years ago
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    Do you mean same common intersection point

  2. anonymous
    • 4 years ago
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    If no all values of m except 7,8

  3. anonymous
    • 4 years ago
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    i need to find a value for the slope for thee first equation so it has a common intersection point with the other 2

  4. anonymous
    • 4 years ago
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    m=16/5

  5. anonymous
    • 4 years ago
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    unfortunately that didn't solve it

  6. Mr.Math
    • 4 years ago
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    Do you know how to find the intersection point of the two given lines?

  7. Mr.Math
    • 4 years ago
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    I mean y=7x+43 and y=8x+53.

  8. Mr.Math
    • 4 years ago
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    The two lines intersect \(7x+43=8x+53 \implies x=-10\). Substitute \(x=-10\) in either equation you get \(y=-70+43=-27\). So the intersection point is \(-10,-27\). Plug this point in the first equation and solve for m.

  9. anonymous
    • 4 years ago
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    Mr Math says the same

  10. anonymous
    • 4 years ago
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    I did it using determinats

  11. Mr.Math
    • 4 years ago
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    Yes, NotSObright is so bright and he's right.

  12. Mr.Math
    • 4 years ago
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    You basically have to solve: \[-27=-10m+5 \implies m=\frac{32}{10}=\frac{16}{5}.\]

  13. anonymous
    • 4 years ago
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    my mistake. Thank you to both of you. The online program I use is picky... did not have to simplify to 16/5. successful using 32/10

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