anonymous
  • anonymous
need to find m so that y=mx+5 has a common intersection point with y=7x+43 and y=8x+53
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Do you mean same common intersection point
anonymous
  • anonymous
If no all values of m except 7,8
anonymous
  • anonymous
i need to find a value for the slope for thee first equation so it has a common intersection point with the other 2

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anonymous
  • anonymous
m=16/5
anonymous
  • anonymous
unfortunately that didn't solve it
Mr.Math
  • Mr.Math
Do you know how to find the intersection point of the two given lines?
Mr.Math
  • Mr.Math
I mean y=7x+43 and y=8x+53.
Mr.Math
  • Mr.Math
The two lines intersect \(7x+43=8x+53 \implies x=-10\). Substitute \(x=-10\) in either equation you get \(y=-70+43=-27\). So the intersection point is \(-10,-27\). Plug this point in the first equation and solve for m.
anonymous
  • anonymous
Mr Math says the same
anonymous
  • anonymous
I did it using determinats
Mr.Math
  • Mr.Math
Yes, NotSObright is so bright and he's right.
Mr.Math
  • Mr.Math
You basically have to solve: \[-27=-10m+5 \implies m=\frac{32}{10}=\frac{16}{5}.\]
anonymous
  • anonymous
my mistake. Thank you to both of you. The online program I use is picky... did not have to simplify to 16/5. successful using 32/10

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