## anonymous 4 years ago can anyone help me solve for y? integral(dy/(100-y)) = integral(xdx)

1. anonymous

$\int\limits_{?}^{?}(1/100-y)= \int\limits_{?}^{?}(x*dx)$

2. TuringTest

$\int\frac{dy}{100-y}=\int xdx$$u=100-y\to du=-dy$$-\int\frac{du}{u}=\int xdx$$-\ln u=\frac12x^2$$\ln(100-y)=-\frac12x^2$$100-y=e^{-x^2/2}$$y=100-e^{-x^2/2}$simplify if you wish...

3. anonymous

ok i see thank you

4. anonymous

I believe there should have been an absolute value sign around the u...which would make it + or minus e^...

5. anonymous

But the rest of it looks good.

6. anonymous

don't for get the c at the end.

7. anonymous

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8. anonymous

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