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anonymous
 4 years ago
sin^2(3x)=1−cos6x , can someone explain the process?
anonymous
 4 years ago
sin^2(3x)=1−cos6x , can someone explain the process?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin^2(3x) = 1  cos^2(3x) might be useful here

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no start with cos 6x = 1  2sin^2(3x) 1  cos 6x = 2sin^2(3x)  are you sure you have the correct expression

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Jimmyrep had the right idea...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1\cos(6x)=2\sin^23x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Not so bright is correct...to sub

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sin^23x=0\] \[3x=n \pi\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i think notsobright is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since u = 3x then cos2(3x)= 12sin^2(3x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is what jimmyrep had to start with...not what is given...make sure you copied it down correctly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0notsobright is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I first thought he/she were trying to verify that they were equal.... but as notsobright and kingkos has indicated...it appears that you were solving for x in which case not so bright was correct...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0values in which the sin^2(3x)=0...or when 3x=npi as was stated. sorry for the confusion.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Got it , thanks again !
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